anonymous
  • anonymous
for the integration of (5x-1)^1/4 I understand that it becomes [(5x-1)^1/4]/(5/4) but I don't understand why it then needs to multiplied by 1/5. I know that you need to get from the power equalling 1/4 to 5/4, so don't you multiply by 5?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
would be from the equivalent of chain rule. remember that the derivative of the integral of (5x -1)^1/4 is itself. so by trying to derive the result you got when you integrated, you should see why the 1/5 should be there. you could also see it by substitution: let u = (5x + 1); du = 5 dx
anonymous
  • anonymous
Substitution probably the easiest way.
anonymous
  • anonymous
Because you have to do the reverse chain rule.

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anonymous
  • anonymous
|dw:1370756169568:dw|
anonymous
  • anonymous
|dw:1370756230956:dw|
anonymous
  • anonymous
I'm sorry I can't read what you have written on the second line of working and I don't really understand.
anonymous
  • anonymous
how do you alter the 1/4 power?
anonymous
  • anonymous
Raise it by 1 then put the modification on the bottom
anonymous
  • anonymous
What do you mean raise it by one? sorry
anonymous
  • anonymous
i used the chain rule and got 5/4(5x-1)^-3/4 so I divided it by 5/4 and then how do I change the -3/4 power?
anonymous
  • anonymous
Use the REVERSE chain rule! Haha
anonymous
  • anonymous
yes I know but in class we learnt to do it that you use the chain rule and then modify the result to get the original, if that makes sense

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