anonymous
  • anonymous
two railway trucks of masses m and 3m move towards each other in opposite direction with speeds 2v and v respectively . these trucks stick together . what is the total speed of trucks after the collision?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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zzr0ck3r
  • zzr0ck3r
conservation
zzr0ck3r
  • zzr0ck3r
3mv - 2mv = 4sm solve for s
zzr0ck3r
  • zzr0ck3r
are you doing momentum conservation?

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anonymous
  • anonymous
the correct answer is v/4 but i dont understand how i can get it
zzr0ck3r
  • zzr0ck3r
3mv - 2mv = 4sm so 4sm=mv so 4s=v so s=v/4
anonymous
  • anonymous
@zzr0ck3r yes it is connservation of momentum
zzr0ck3r
  • zzr0ck3r
understand?
anonymous
  • anonymous
yes. best response :)
anonymous
  • anonymous
Let's denote the direction the mass \(m\) is moving in as positive. We know that in every collision momentum is conserved. Let's compute our initial momenta:$$p_0=m(2v)=2mv\\p_1=(3m)(-v)=-3mv$$... so our net momentum is given by \(2mv-3mv=-mv\). After the collision, we're left with one body of combined mass, i.e. \(M=m+3m=4m\). We wish to determine its speed. We find its momentum to be \(Mv'=4mv'\). As momentum is conserved, we know \(-mv=4mv'\). Now solve for \(v'\):$$-mv=4mv'\\-v=4v'\\v'=-\frac14v$$
anonymous
  • anonymous
i.e. post-collision we will be travelling in the direction of \(3m\) mass at a quarter of its initial speed. :-) this should make intuitive sense.

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