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.Sam.Best ResponseYou've already chosen the best response.2
A sample of ethyl propanoate is hydrolysed by heating under reflux with aqueous sodium hydroxide. The two organic products of the hydrolysis are separated, purified and weighed. Out of the total mass of products obtained, what is the percentage by mass of each product? \(\color{blue}{Ans:}32.4% and 67.6 \)% and \(67.6\)%
 10 months ago

.Sam.Best ResponseYou've already chosen the best response.2
\[M_r(CH_3CH_2COOCH_2CH_3)=102g/mol\] Separated compounds should be carbox and alcohol right \[M_r(CH_3CH_2COOH)=74g/mol\] \[M_r(HOCH_2CH_3)=46g/mol\] What I've found was 38.3% and 61.7%
 10 months ago

mathsloverBest ResponseYou've already chosen the best response.0
You are correct @.Sam.
 10 months ago

.Sam.Best ResponseYou've already chosen the best response.2
But the answer is 32.4% and 67.6% :(
 10 months ago

mathsloverBest ResponseYou've already chosen the best response.0
The answer (from wherever it has been taken) is wrong.
 10 months ago

mathsloverBest ResponseYou've already chosen the best response.0
The products of the hydrolysis are correct; the molecular masses are also correct then there is nothing left which could be wrong.
 10 months ago

.Sam.Best ResponseYou've already chosen the best response.2
Hmm I still can't trust my answer, we'll wait for more opinions from others okay :)
 10 months ago

emcrazy14Best ResponseYou've already chosen the best response.4
You did a mistake in there. The base hydrolysis of esters results in a sodium salt rather than carboxylic acid itself. So, here you'll get sodium propanoate i.e CH3CH2COONa So your Mr will be 96. Now, your percentage by mass of each product will be: (96/142) x 100= 67.6% (46/142) x 100= 32.4%
 10 months ago

.Sam.Best ResponseYou've already chosen the best response.2
Oh yeah we're not using \(H_2O\) to hydrolyse that ester, derp... Okay got it, thanks @emcrazy14 :)
 10 months ago

mathsloverBest ResponseYou've already chosen the best response.0
Oh, I did 96 + 46 = 162 :D , good work @emcrazy14
 10 months ago

KLRCBest ResponseYou've already chosen the best response.0
First of all thanks A LOT for posting this question Sam and No wonder, I was thinking that why is he writing a product of esterification?? instead of a sodium salt?? either way thanks you all! ;D
 3 days ago

KLRCBest ResponseYou've already chosen the best response.0
and @emcrazy14 you too!! thanks!!! :D
 3 days ago
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