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.Sam.
 one year ago
Best ResponseYou've already chosen the best response.3A sample of ethyl propanoate is hydrolysed by heating under reflux with aqueous sodium hydroxide. The two organic products of the hydrolysis are separated, purified and weighed. Out of the total mass of products obtained, what is the percentage by mass of each product? \(\color{blue}{Ans:}32.4% and 67.6 \)% and \(67.6\)%

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.3\[M_r(CH_3CH_2COOCH_2CH_3)=102g/mol\] Separated compounds should be carbox and alcohol right \[M_r(CH_3CH_2COOH)=74g/mol\] \[M_r(HOCH_2CH_3)=46g/mol\] What I've found was 38.3% and 61.7%

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0You are correct @.Sam.

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.3But the answer is 32.4% and 67.6% :(

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0The answer (from wherever it has been taken) is wrong.

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0The products of the hydrolysis are correct; the molecular masses are also correct then there is nothing left which could be wrong.

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.3Hmm I still can't trust my answer, we'll wait for more opinions from others okay :)

emcrazy14
 one year ago
Best ResponseYou've already chosen the best response.4You did a mistake in there. The base hydrolysis of esters results in a sodium salt rather than carboxylic acid itself. So, here you'll get sodium propanoate i.e CH3CH2COONa So your Mr will be 96. Now, your percentage by mass of each product will be: (96/142) x 100= 67.6% (46/142) x 100= 32.4%

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.3Oh yeah we're not using \(H_2O\) to hydrolyse that ester, derp... Okay got it, thanks @emcrazy14 :)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I did 96 + 46 = 162 :D , good work @emcrazy14

KLRC
 10 months ago
Best ResponseYou've already chosen the best response.0First of all thanks A LOT for posting this question Sam and No wonder, I was thinking that why is he writing a product of esterification?? instead of a sodium salt?? either way thanks you all! ;D

KLRC
 10 months ago
Best ResponseYou've already chosen the best response.0and @emcrazy14 you too!! thanks!!! :D
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