anonymous
  • anonymous
What is the electric charge of a ring-shaped metallic washer ?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Equation of a density of a ring \[\rho(x,y)=(x^2+y^2)^{3/2}\]
anonymous
  • anonymous
Sorry , Real={(x,y)in Real^2 | 1le x^2+y^2 le 2}
anonymous
  • anonymous
x^2+y^2-xy=\frac{x^2}{2}+\frac{y^2}{2}+\frac{(x-y)^2}{2} I Think This What You Have To Do Its Been A While So You Might Want To Double Check

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More answers

anonymous
  • anonymous
Did You try Working it Out ?
anonymous
  • anonymous
Not sure, but I came up with this
1 Attachment
anonymous
  • anonymous
So the charge is π C
dan815
  • dan815
i dont have this course till my next year, but whats the formula u are trying to implement? u want to take the integral of the density at all volume element?
anonymous
  • anonymous
Hey ! Yes since the electric charge can be determined by density and volume it occupies, I decided to implement mass integration but for charge. Something still feels not quite right
anonymous
  • anonymous
Ohh Hold On I Think there is something Missing in that case i was using a different Way to solve it /:
dan815
  • dan815
yes thats what i was going to suggest the mass formula for this
dan815
  • dan815
but what is that other found on your function?
dan815
  • dan815
1
dan815
  • dan815
bound*
dan815
  • dan815
|dw:1370784948370:dw|
dan815
  • dan815
ur gonna have to change the order of integration to what suits this best
dan815
  • dan815
probably do it like from plane z = 1 to z=x^2+y^2 da= rdrd@; r from 1 to sqrt2 and @ from = 0 to 2pi
dan815
  • dan815
|dw:1370785364405:dw|
dan815
  • dan815
|dw:1370785425297:dw|
dan815
  • dan815
slightly confused about my z bound, maybe u can figure it out if that is right or how to fix it, bye
anonymous
  • anonymous
Thank you ! That's the method ! :)
anonymous
  • anonymous
Big fan of your graphs btw.
dan815
  • dan815
haha thanks lol

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