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Do you know the formula for the area of a triangle?
okay what is it?
(1/2) * base * height
Your trapezoid will look like this in a more detailed manner: |dw:1370794837531:dw| So I think you can try to use proportions with some parts of this trapezoid to get the area. You can also just use the basic trapezoid formula for area.
good so lets split the parallelogram into two triangles
remember it asked for the area of two triangles and whether they will have the same area so no you can not use a proportion.
The two triangles are similar and the following ratios exist. EB/EA = EC/ED = BC/AD = 10/25 Calculate EB using the EB/EA expressed as (EB )/(EB + 14) =10/25 EB=28/3. Similarly solve of EC, EC/(EC+13) = 10/25=2/5. EC =26/3 Now that all three sides of each triangle are now known, us Heron's equation to solve for each triangles area.
Did you read the problem it clearly states to split the parallelogram into two triangles and solve for the area of both and compare I don't know what you are doing.
Calculate S=.5(28/3 +10 + 26/3)=.5 ( 10 + 18)=14 Area(BEC) = SqRt[14(14-28/3)(14 - 26/3)(14-10)] = 37 1/3 Calculate S for Area (AED)=.5(70 +100/3)=51 2/3 Calculate Area for large triangle AEB. A=SqRt [51 2/3(51 2/3 - 25)(51 2/3 - 70/3)(51 2/3 - 65/3)]=1082 sq units Area of trapezoid = 1082-37 1/3 = 1044 2/3 sq units.
Just arranging the problem into two triangles. There may be errors in the arithmetic, but the procedure will provide a solution. from No. 1.