A community for students.
Here's the question you clicked on:
 0 viewing
AJACW22
 2 years ago
Suppose x is a normally distributed random variable with μ = 14 and σ =2. Find each of the following probabilities.
a. P (x ≥ 14.5) b. P (x ≤ 11) c. P (14.42 ≤ x ≤ 19.46) d. P (9.12 ≤ x ≤ 16.77)
AJACW22
 2 years ago
Suppose x is a normally distributed random variable with μ = 14 and σ =2. Find each of the following probabilities. a. P (x ≥ 14.5) b. P (x ≤ 11) c. P (14.42 ≤ x ≤ 19.46) d. P (9.12 ≤ x ≤ 16.77)

This Question is Closed

becca1703
 2 years ago
Best ResponseYou've already chosen the best response.1a. P(x ≥14.5) = 1P(x≤14.5) =1P(z≤(14.514)/2) =1P(z≤0.25) =10.59871 (using normal table) = 0.50129 I'll try to do the others next.

becca1703
 2 years ago
Best ResponseYou've already chosen the best response.1b. P(x≤11) = P(z≤(1114)/2) =P(z≤1.5) =1 0.93319 (ve so do 1 minus) = 0.06671

becca1703
 2 years ago
Best ResponseYou've already chosen the best response.1c. Split into P(x ≥14.42)  P(x ≤19.46) =P(z ≥ (14.4214)/2)  P(z ≤ (19.461)/2) =P(z ≥ 0.21)  P(z ≤ 2.73) =0.58317 + 0.99683  =0.58

becca1703
 2 years ago
Best ResponseYou've already chosen the best response.1d. P(x ≥ 9.12)  P(x ≤ 16.77) =P(z ≥ 2.44)  P(z ≤ 1.385) =0.99266 + 0.91774  1 =0.07492

becca1703
 2 years ago
Best ResponseYou've already chosen the best response.1actually that last line should be 0.9104

AJACW22
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you. I have another one with different numbers. Sorry I didnt get a chance to solve the first one.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.