anonymous
  • anonymous
Find the area of the region between the curves y=sin(x), y=sin(2x), x=0, x=pi/2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Jhannybean
  • Jhannybean
since we are asked to find the area between a region where parts of the integral are where \(\large \sin(2x)\ge \sin(x)\) and other parts where \(\large \sin(x) \ge \sin(2x)\) you have to split up the integral. \[\large A= \int\limits_{0}^{\pi/2} |\sin(2x)-\sin(x)|dx=A_{1}+A_{2}\] A1 refers to the first area of the integral, and A2 refers to the second area of the area|dw:1370801676574:dw|
anonymous
  • anonymous
omg thank you sooo much you're amazing!! so you just subtract the top and bottom right?
Jhannybean
  • Jhannybean
I believe so, yes

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anonymous
  • anonymous
okk sweet thank you!!
Jhannybean
  • Jhannybean
you're going to split the integral into two parts, first from 0 to pi/3 i believe? and then from pi/3 to pi/2
Jhannybean
  • Jhannybean
(the picture above wasnt drawn to scale :\ |dw:1370802517810:dw|
anonymous
  • anonymous
ohhh ok gotcha

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