anonymous
  • anonymous
MIDTERMS I NEED HEL0 UNDERSTANDING! THE UNIT CIRCLE.Help Let P(t) be the point on the unit circle U that corresponds to t.If P (t) has the given retangular coordnates find a)P(T+PIE) B)P(t-pie) c)P(-t) d)P(-t-pie) for (3/5,4/5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
help with exams is prohibited
anonymous
  • anonymous
please read the anti-cheating policy under the terms and conditions
anonymous
  • anonymous
unless you have something else to say @Mertsj

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anonymous
  • anonymous
I AM PRACTICING FOR EXAMS I DONT HAVE A MIDTERM IN FRONT OF ME
anonymous
  • anonymous
next time rephrase your question as it is very misleading
anonymous
  • anonymous
i need help understanding how is that cheating exactly?
anonymous
  • anonymous
because the point of an exam/test is to test your own understanding of the subject
anonymous
  • anonymous
i didnt know people have take home midterm test for maths ...n e ways can someone please help me
zepdrix
  • zepdrix
The wording of this question is confusing... So at the end there, is that an ordered pair like this? \[\large \left(t,\;p(t)\right) \qquad=\qquad \left(\frac{3}{5},\;\frac{4}{5}\right)\]
zepdrix
  • zepdrix
Oh p(t) is the given `rectangular` coordinates.. so that's (x,y) i guess? This is worded so strange :( I can't make sense of it.
anonymous
  • anonymous
yes i think so
zepdrix
  • zepdrix
|dw:1370818396386:dw|
zepdrix
  • zepdrix
Does this drawing make sense to you? I've drawn the unit circle, and labeled our x and y coordinates. This particular location we're calling \(\large P(t)\).
anonymous
  • anonymous
with this can you just plot the graph to see uwhat u r doing also right?
zepdrix
  • zepdrix
Ya it helps to visualize it I think :)
anonymous
  • anonymous
yes it makes sense
zepdrix
  • zepdrix
So if this is our point \(\large P(t)\), and \(\large t\) represents some distance along the unit circle, what would adding \(\large \pi\) to our \(\large t\) do? So if you remember back to the unit circle, one full rotation is \(\large 2\pi\). So a half-rotation is just \(\large \pi\). So if we add \(\large \pi\) to our \(\large t\), it's another way of saying "rotate your point halfway around the circle"
anonymous
  • anonymous
ok
zepdrix
  • zepdrix
|dw:1370818734641:dw|
zepdrix
  • zepdrix
Understand what I did there? We spun around the circle 180 degrees, or pi radians.
anonymous
  • anonymous
y
zepdrix
  • zepdrix
So we've figured out that if \[\large P(t)=\left(\frac{3}{5},\;\frac{4}{5}\right)\] Then, \[\large P(t+\pi)=\left(-\frac{3}{5},\;-\frac{4}{5}\right)\]
zepdrix
  • zepdrix
|dw:1370818972646:dw|Just to remind you, if we ADDED pi, it means we spun counter-clockwise.
zepdrix
  • zepdrix
So what do you think we'll get for the part b)
zepdrix
  • zepdrix
We're SUBTRACTING pi, so we'll spin the opposite direction. But what point do you think we'll land at if we're spinning half way around?
zepdrix
  • zepdrix
Hmm maybe i'm not reading the question correctly.. seems like we're going to get the same answer for all of these parts.. hmm
anonymous
  • anonymous
oh...u know of anyone who is familar with this topic
zepdrix
  • zepdrix
@Zarkon This guy is a smarty pants, maybe he can make sense of it D:
anonymous
  • anonymous
k thanks

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