anonymous
  • anonymous
HELP - Find the area of a regular hexagon with side length of 5 cm. Round your answer to the nearest tenth. - HELP
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
21.7 cm2 32.5 cm2 112.5 cm2 65 cm2
mathstudent55
  • mathstudent55
|dw:1370835369419:dw|
mathstudent55
  • mathstudent55
|dw:1370835426789:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathstudent55
  • mathstudent55
Each interior angle measures 120 degrees. |dw:1370835520501:dw|
mathstudent55
  • mathstudent55
For each triangle, the two angles near the side of the haxagon are 60 degrees each, so the third angle is also 60 degrees. |dw:1370835651695:dw|
mathstudent55
  • mathstudent55
|dw:1370835729460:dw|
mathstudent55
  • mathstudent55
Now you need to find the area of an equilateral triangle whose sides measure 5 cm.
mathstudent55
  • mathstudent55
Are you following this?
anonymous
  • anonymous
5*5/2? =12.5
mathstudent55
  • mathstudent55
|dw:1370835819749:dw|
mathstudent55
  • mathstudent55
The small triangle on the right has one leg measuring 2.5 cm and a hypotenuse measurung 5 cm. With the Pytagoras theorem, we can find h, the measure of the other leg, which is also the height of the large triangle.
anonymous
  • anonymous
I got 5.59 for the height.
mathstudent55
  • mathstudent55
|dw:1370836035215:dw|
mathstudent55
  • mathstudent55
The height can't be 5.59 because the hypotenuse is 5, and the height can't be larger than the hypotenuse.
anonymous
  • anonymous
Oh.. I put them in the wrong posistion. I did 2.5^2 + 5^2 = h^2
mathstudent55
  • mathstudent55
|dw:1370836251965:dw|
mathstudent55
  • mathstudent55
You need to add the squares of the legs to equal the square of the hypotenuse. That's why it's 2.5^2 + h^2 = 5^2
anonymous
  • anonymous
Lol yeah.
mathstudent55
  • mathstudent55
Now we see that for one triangle, we have a base of 5 cm and a height of sqrt(18.75) cm. The area of a triangle is A = (1/2)bh, where b = base, and h = height. Since the hexagon is made up of 6 congruent triangles, the area of the hexagon is 6 times the area of the triangle.
mathstudent55
  • mathstudent55
AH = area of the hexagon AH = 6(1/2)bh = 3bh AH = 3 * 5 cm * sqrt(18.75) cm AH = 65.0 cm^2
anonymous
  • anonymous
See, I didn't know that I had to break the Hexagon into 6 triangles... But thank you so much!
mathstudent55
  • mathstudent55
We break it up into simple shapes that we are familiar with, such as a triangle.
mathstudent55
  • mathstudent55
You're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.