anonymous
  • anonymous
Find the area of the triangle. Give to the nearest tenth.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
Would you know if this is a right triangle?
anonymous
  • anonymous
i think

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UnkleRhaukus
  • UnkleRhaukus
|dw:1370842950488:dw|
UnkleRhaukus
  • UnkleRhaukus
|dw:1370843009047:dw|
UnkleRhaukus
  • UnkleRhaukus
\[\boxed{\sin\theta=\dfrac{\text{opposite side}}{\text{hypotenuse}}}\] \[\sin\theta\times {\text{hypotenuse}}={\text{opposite side}}\]
UnkleRhaukus
  • UnkleRhaukus
|dw:1370843147205:dw|
anonymous
  • anonymous
what is the equation
anonymous
  • anonymous
You'll need a calculator btw
UnkleRhaukus
  • UnkleRhaukus
* The area of the big triangle is equal to the half the base times the height, find the height by finding the opposite side of the right angled triangle
anonymous
  • anonymous
sin 73=x/12 multiply both sides by 12 and x= (sin 73) 12
anonymous
  • anonymous
plug it in to your sci calculator and you get 11.5 (this is the height of the triangle)
anonymous
  • anonymous
Then just multiply that by the base which is 11 cm (11)(11.5)=126.2
anonymous
  • anonymous
The unit is cm^2
anonymous
  • anonymous
\[\frac{1}{2}*11*12* \text{Sin}[73{}^{\circ}]=63.1161 \]
anonymous
  • anonymous
126.2/2=63.1 cm^2
UnkleRhaukus
  • UnkleRhaukus
|dw:1370843902533:dw|

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