anonymous
  • anonymous
why is it that when 'using intercepts and symmetry to sketch a graph' does the equation x-y^2=1 get the y replaced w/ a negative [looking like this -> x-(-y)^2=1 ] wind up being simplified to x-y^2=1 instead of being simplified to x+y^2=1 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dan815
  • dan815
what thats messed up forget all about that stuff
anonymous
  • anonymous
aw, well :( unfortunately I can not because it is a fundamental question for me to understand the section but thanks
Jhannybean
  • Jhannybean
\[\large x-(-y)^2 = 1 \] solve the (-y)^2 first. \[\large (-y^2) = (-y)(-y) = y^2\]now replace (-y)^2 with y^2\[\large x-y^2 = 1\]

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Jhannybean
  • Jhannybean
The y doesn't get replaced by a negative, you just have to remember to solve for your (-y)^2 first before simplifying x-(-y)^2 into x+y^2.
anonymous
  • anonymous
thank you, wowww I cant believe I didn't catch that
dan815
  • dan815
i said forget all this stuff because i dont like how ur thinking about equations
dan815
  • dan815
we dont think about all this stuff, when ur just building a vertex equations, u just wanna kinda build ur equation knowing where the Vertex will be
dan815
  • dan815
dont be restrained to these rules, learn to adapt then u will find math easier as u get better at adapting to different methods
anonymous
  • anonymous
okidiki, thank you foor that insight
anonymous
  • anonymous
okidoki, lol

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