anonymous
  • anonymous
solve 5x^2-3x=(7x^2+5x)-(2x^2+16)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hartnn
  • hartnn
combine like terms, whats 7x^2-2x^2 on right side ?
anonymous
  • anonymous
5x
hartnn
  • hartnn
5x or 5x^2 ?

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anonymous
  • anonymous
5x^2
hartnn
  • hartnn
yes, now bring that 5x^2 on left side, you know how ?
anonymous
  • anonymous
subtraction?
hartnn
  • hartnn
correct!
anonymous
  • anonymous
\[5x ^{2}-3x=7x ^{2}+5x-2x ^{2}-16\]
anonymous
  • anonymous
so it becomes \[8x=16\] and x=2
hartnn
  • hartnn
so, what will u get after subtracting 5x^2 on both sides ?
anonymous
  • anonymous
so the answer is -2 ?
hartnn
  • hartnn
-2 ? how u got that ?
anonymous
  • anonymous
because when i subtract -5x from the left side which was -5x-3x it gave me only -3x on the left side. then on the right side i was left with 5x+16
anonymous
  • anonymous
then i subtracted 5x and subtracted it from -3x
hartnn
  • hartnn
actually on right side, it'll be 5x-16 because (7x^2+5x)-(2x^2+16) = 5x^2 +5x -16
anonymous
  • anonymous
u have to subtract 5x from both sides so u will get -8x=-16
anonymous
  • anonymous
therefore x=2
hartnn
  • hartnn
then as per what you wrote, i am sure you got -8x on left -8x = -16 will actually give u x=2 got this ?

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