Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

|dw:1370881868506:dw|At what time will the particles collide?

|dw:1370882089218:dw|

But am I right?

i see that is what, acceleration up top and speed on the bottom?

Yes.

\[\frac12at^2+v_it+d_i=\frac12\alpha t^2+\beta_it+\delta d_i\]
\[\frac12t^2+4t+0=-\frac12t^2+2t+30\]

im wondering it that should be a -2t over on the right

since velocity is a vector, all assume -2t
\[\frac12t^2+4t=-\frac12t^2-2t+30\]
\[t^2+6t=30\]

Well, so that leads to \(t^2 + 6t - 30\)... so I am right?

Thanks, another one coming up: this time with circles!

Yes this is correct. Choose solution with t>0.

Yes, already done. Thank you