ParthKohli
  • ParthKohli
Classical Mechanics: circular motion
Physics
jamiebookeater
  • jamiebookeater
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ParthKohli
  • ParthKohli
|dw:1370882795176:dw|Find the time when the particles collide.
anonymous
  • anonymous
What is the thing written on the left side of the diagram?
ParthKohli
  • ParthKohli
@kutabs 2 rad/s So this time I tried to do with the fact that \(\theta_1 + \theta_2 = \dfrac{3\pi}{2}\) and using the equations of motion.

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ParthKohli
  • ParthKohli
That isn't a problem at all. The problem is that there are more questions. I am not able to figure out \(a_R\) of each particle at the time of collision.
amistre64
  • amistre64
is teh acceleration given for the 2rad/sec speed?
ParthKohli
  • ParthKohli
Yes.
ParthKohli
  • ParthKohli
Ah, no worries, I get it. It's easy to find \(v\) for each particle after I get the \(t\). Thank you for the time guys.
amistre64
  • amistre64
this is then the same as the last question really\[-\frac12a_1t^2-v_1t+d_1=\frac12a_2t^2+v_2t+d_2\]
ParthKohli
  • ParthKohli
\[\theta_1 = 2t \]\[\theta_2 = t + t^2\]Thank you, I can manage after that.
ParthKohli
  • ParthKohli
I was just having this little confusion that I cleared myself. :-|
anonymous
  • anonymous
Let them meet at the angle theta as shown |dw:1370883098101:dw| For 1: Covering pi/2+(pi/2-theta)= omega*t For 2: Covering pi/2+theta= omega*t+1/2*alpha*(t^2)
anonymous
  • anonymous
Now from these two equations 1&2there are 2 variables theta and time (t). Solve them, and you'll get the result.

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