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ParthKohli

  • one year ago

Classical Mechanics: circular motion

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  1. ParthKohli
    • one year ago
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    |dw:1370882795176:dw|Find the time when the particles collide.

  2. kutabs
    • one year ago
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    What is the thing written on the left side of the diagram?

  3. ParthKohli
    • one year ago
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    @kutabs 2 rad/s So this time I tried to do with the fact that \(\theta_1 + \theta_2 = \dfrac{3\pi}{2}\) and using the equations of motion.

  4. ParthKohli
    • one year ago
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    That isn't a problem at all. The problem is that there are more questions. I am not able to figure out \(a_R\) of each particle at the time of collision.

  5. amistre64
    • one year ago
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    is teh acceleration given for the 2rad/sec speed?

  6. ParthKohli
    • one year ago
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    Yes.

  7. ParthKohli
    • one year ago
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    Ah, no worries, I get it. It's easy to find \(v\) for each particle after I get the \(t\). Thank you for the time guys.

  8. amistre64
    • one year ago
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    this is then the same as the last question really\[-\frac12a_1t^2-v_1t+d_1=\frac12a_2t^2+v_2t+d_2\]

  9. ParthKohli
    • one year ago
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    \[\theta_1 = 2t \]\[\theta_2 = t + t^2\]Thank you, I can manage after that.

  10. ParthKohli
    • one year ago
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    I was just having this little confusion that I cleared myself. :-|

  11. kutabs
    • one year ago
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    Let them meet at the angle theta as shown |dw:1370883098101:dw| For 1: Covering pi/2+(pi/2-theta)= omega*t For 2: Covering pi/2+theta= omega*t+1/2*alpha*(t^2)

  12. kutabs
    • one year ago
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    Now from these two equations 1&2there are 2 variables theta and time (t). Solve them, and you'll get the result.

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