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ParthKohliBest ResponseYou've already chosen the best response.0
dw:1370882795176:dwFind the time when the particles collide.
 10 months ago

kutabsBest ResponseYou've already chosen the best response.0
What is the thing written on the left side of the diagram?
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
@kutabs 2 rad/s So this time I tried to do with the fact that \(\theta_1 + \theta_2 = \dfrac{3\pi}{2}\) and using the equations of motion.
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
That isn't a problem at all. The problem is that there are more questions. I am not able to figure out \(a_R\) of each particle at the time of collision.
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
is teh acceleration given for the 2rad/sec speed?
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
Ah, no worries, I get it. It's easy to find \(v\) for each particle after I get the \(t\). Thank you for the time guys.
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
this is then the same as the last question really\[\frac12a_1t^2v_1t+d_1=\frac12a_2t^2+v_2t+d_2\]
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
\[\theta_1 = 2t \]\[\theta_2 = t + t^2\]Thank you, I can manage after that.
 10 months ago

ParthKohliBest ResponseYou've already chosen the best response.0
I was just having this little confusion that I cleared myself. :
 10 months ago

kutabsBest ResponseYou've already chosen the best response.0
Let them meet at the angle theta as shown dw:1370883098101:dw For 1: Covering pi/2+(pi/2theta)= omega*t For 2: Covering pi/2+theta= omega*t+1/2*alpha*(t^2)
 10 months ago

kutabsBest ResponseYou've already chosen the best response.0
Now from these two equations 1&2there are 2 variables theta and time (t). Solve them, and you'll get the result.
 10 months ago
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