JA1
  • JA1
I a trying to find a GCF to factor out this quadratic equation, can you help? 0 = -x^2 + 2x + 15
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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JA1
  • JA1
@mathstudent55
eSpeX
  • eSpeX
What is something that will go into every term in your equation?
JA1
  • JA1
Excuse my mentality, I have been doing these right for the past half hour but I guess my mind decided to troll me on this question *facepalm*

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JA1
  • JA1
Thanks for bringing me to senses, also would it be -x because I have never seen -x before :/ @eSpeX
eSpeX
  • eSpeX
You are on the right track and I apologize if I came across as condescending. Your last term does not have a 'x' in it though...
JA1
  • JA1
No your fine :), oh and the way the lesson taught me is to just do this when there is no GCF: (x +/- #)(x +/- #)
JA1
  • JA1
Wait, grrr I am wrong, I am trying to find the GCF of 2 and 15 my bad
eSpeX
  • eSpeX
Rather than try a -x, which as we said does not exist in every term, what about -1?
eSpeX
  • eSpeX
GCF or are you factoring?
JA1
  • JA1
Yes but then the product would be negative and so it would be wrong right? Since 15 is positive and so is 2
JA1
  • JA1
I need to find two numbers that the sum is 2 and the product is 15
eSpeX
  • eSpeX
No, you are correct, and so what multiplies together to create -15 and adds together to get -2?
JA1
  • JA1
The original equation is: x^2 = 2x + 15
JA1
  • JA1
Well in that case it would be +5 -3
JA1
  • JA1
nono -5 +3
eSpeX
  • eSpeX
I would have pushed everything to the left as to keep my square positive. And +5-3=+2
eSpeX
  • eSpeX
Exactly. Good job. So your final result is?
JA1
  • JA1
(x + 3)(x - 5) x + 3 = 0 OR x - 5 = 0 -3 -3 +5 +5 x = -3 AND x = 5 right?
eSpeX
  • eSpeX
Yes, that is right. I would point out though that what you have done is considered "factoring" and not finding the GCF. :)
JA1
  • JA1
Yes me and correct terminology do not get along xD but I usually understand it that way in my head but thanks :D
eSpeX
  • eSpeX
You're welcome. Best of luck.
JA1
  • JA1
Thanks.

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