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Ed25Best ResponseYou've already chosen the best response.0
Using Green's theorem I got 2 as result, but Wolfram says it is 5/3. Can somebody check on this?
 10 months ago

mykoBest ResponseYou've already chosen the best response.0
express y as function of x and substitute into the integral: y=1x
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
I did it already. thats how I get 2
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
can you walk me thru your application of greens thrm
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
partial derivatives are: dp/dy=3 and dq/dx=y, (i know that d should be written different)
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
and then integral is: dw:1370887152616:dw
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
boundaries for X goes from 0 to 1 and for Y they are 0 and 1x, am I right?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
y = 0 to y = x+1 x = 0 to x = 1
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
well, dxdy or dydx?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
dydx is intx[0,1] inty[0,1x]
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
(1x)^2 / 2 from 0 to 1
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
i forgot to yup the 3 :/
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\int_{0}^{1}\frac{(1x)^2}{2}+3(1x)~dx\]
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
ok, i've found a mistake in my calculation, i'm doing it now directly by parametrization of curves, will see the result
 10 months ago

Ed25Best ResponseYou've already chosen the best response.0
for C1: x=t, y=0, 0<=t<=1 and Integral is = 1 C2: x=1t, y=t, 0<=t<=1, int=1/3 c3: x=0, y=1t, 0<=t<=1, int=0
 10 months ago

experimentXBest ResponseYou've already chosen the best response.1
about surface integrals, \[ \iint dx dy \] shoudl you give areadw:1370889753653:dw choose any way you like to integrate ... if this gives you your required area then your parametrization if correct. just put the function inside and integrate it.
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\int_{0}^{1}\int_{0}^{1y}y+3~dx~dy\] \[\int_{0}^{1}y(1y)+3(1y)~dy\] \[\int_{0}^{1}y^22y+3~dy\] \[\frac{1}{3}1+3\]
 10 months ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1370889905032:dw
 10 months ago
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