anonymous
  • anonymous
The polynomial 8x2 - 9 is a difference of squares. T/F?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
8x^2-9**
anonymous
  • anonymous
I think true but people are saying false?
whpalmer4
  • whpalmer4
Difference of squares has the form \(a^2-b^2\) Can you find a value for \(a\) and \(b\) to match your equation? Obviously, \(b=3\) is half of the job, what about for \(a^2 = 8x^2\)?

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anonymous
  • anonymous
?? All I asked was "True or False"
whpalmer4
  • whpalmer4
Yes, and I'm trying to help you know the answer without asking us :-)
whpalmer4
  • whpalmer4
\[a^2=8x^2\]Can you solve that for \(a\)?
anonymous
  • anonymous
I'm going with false.
whpalmer4
  • whpalmer4
Take the square root of both sides: \[\sqrt{a^2} = \sqrt{8x^2}\]Remember that \(\sqrt{a^2} = a\) \[a = \sqrt{8}*\sqrt{x^2} = x\sqrt{8}\] So we can see that it is TRUE, because \[(x\sqrt{8})^2-3^2 = 8x^2-9\]

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