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tomiko
 one year ago
need help with this double integral question :)
http://gyazo.com/a3e6e7133a02d92949f4a14f0cb3961e
tomiko
 one year ago
need help with this double integral question :) http://gyazo.com/a3e6e7133a02d92949f4a14f0cb3961e

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FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1What are you stuck with?

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{\pi}^{2\pi}\int\limits_{0}^{1}xsin(xy)dxdy\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3since your limits are constants; you can prolly more easily swap it for dydx

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3which proff did ... ironically :)

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1IRONICALLY?!?! LOOOOOOOOOOL

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[\int\limits_{\pi}^{2\pi}\int\limits_{0}^{1}xsin(xy)~dydx\] \[\int\limits_{\pi}^{2\pi}\left(\int\limits_{0}^{1}xsin(xy)~dy\right)dx\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3doh ... loathesome integrals!!

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1@amistre64 doesn't the zero to one have to stick with the dx differential though?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[\int_{x=0}^{x=1}\left(\int_{y=\pi}^{y=2\pi}xsin(xy)~dy\right)dx\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3it tends to help me out if i label the integrals ....

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1Isn't the general integral of that xsin(xy)/y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[\int_{x=0}^{x=1}\left(\int_{y=\pi}^{y=2\pi}xsin(xy)~dy\right)dx\] \[\int_{x=0}^{x=1}cos(2\pi~x)+cos(\pi~x)~dx\]

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1I thought you didn't have to do parts integration since your X term out front evidently doesn't have a Y in it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3you still have to integrate your limits respectively x = [0,1] has to address your dx y = [pi, 2pi] has to address your dy

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3the dx, dy parts tells you what you focus on while leaving the other term a constant

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1LOLOL I forgot about that

FutureMathProfessor
 one year ago
Best ResponseYou've already chosen the best response.1I didn't realize you were evaluating limits in your 2nd step of that response

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3let x = k int k sin(ky) dy > cos(ky) cos(x 2pi)  cos(x pi)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3int cos(x pi)  cos(x 2pi) dx sin(x pi)/pi  sin(x 2pi)/2pi (sin(pi)/pi  sin(2pi)/2pi)  (sin(0 pi)/pi  sin(0 2pi)/2pi) (0  0)  (0  0) so with any luck :)
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