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anonymous
 3 years ago
need help with this double integral question :)
http://gyazo.com/a3e6e7133a02d92949f4a14f0cb3961e
anonymous
 3 years ago
need help with this double integral question :) http://gyazo.com/a3e6e7133a02d92949f4a14f0cb3961e

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What are you stuck with?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{\pi}^{2\pi}\int\limits_{0}^{1}xsin(xy)dxdy\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3since your limits are constants; you can prolly more easily swap it for dydx

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3which proff did ... ironically :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0IRONICALLY?!?! LOOOOOOOOOOL

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3\[\int\limits_{\pi}^{2\pi}\int\limits_{0}^{1}xsin(xy)~dydx\] \[\int\limits_{\pi}^{2\pi}\left(\int\limits_{0}^{1}xsin(xy)~dy\right)dx\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3doh ... loathesome integrals!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 doesn't the zero to one have to stick with the dx differential though?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3\[\int_{x=0}^{x=1}\left(\int_{y=\pi}^{y=2\pi}xsin(xy)~dy\right)dx\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3it tends to help me out if i label the integrals ....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Isn't the general integral of that xsin(xy)/y

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3\[\int_{x=0}^{x=1}\left(\int_{y=\pi}^{y=2\pi}xsin(xy)~dy\right)dx\] \[\int_{x=0}^{x=1}cos(2\pi~x)+cos(\pi~x)~dx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I thought you didn't have to do parts integration since your X term out front evidently doesn't have a Y in it?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3you still have to integrate your limits respectively x = [0,1] has to address your dx y = [pi, 2pi] has to address your dy

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3the dx, dy parts tells you what you focus on while leaving the other term a constant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LOLOL I forgot about that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I didn't realize you were evaluating limits in your 2nd step of that response

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3let x = k int k sin(ky) dy > cos(ky) cos(x 2pi)  cos(x pi)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3int cos(x pi)  cos(x 2pi) dx sin(x pi)/pi  sin(x 2pi)/2pi (sin(pi)/pi  sin(2pi)/2pi)  (sin(0 pi)/pi  sin(0 2pi)/2pi) (0  0)  (0  0) so with any luck :)
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