anonymous
  • anonymous
An even trickier double integration question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Switch to polar coordinates to solve:|dw:1370925546848:dw|
anonymous
  • anonymous
Its getting bigger as Cline-Circle is getting bigger to cline-Circle approaches 90 degrees
anonymous
  • anonymous
Haha I know me too

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anonymous
  • anonymous
So what would the limits of integration be
anonymous
  • anonymous
change y to rsintta?
dan815
  • dan815
ya but we cant have that as our function
dan815
  • dan815
u gotta represent r as a function of theta
dan815
  • dan815
@oldrin.bataku how u do this?
anonymous
  • anonymous
Haha calling in the big guns @oldrin.bataku that's the way to do it @dan815
anonymous
  • anonymous
The problem is we don't know how far that R is
anonymous
  • anonymous
OMFG I forgot I pirated a solutions manual for this problem. Give me a sec
anonymous
  • anonymous
You guys are noobs this is how I did it http://gyazo.com/1c77f2c56b32485c7d5cd70ff9b5d817.png
anonymous
  • anonymous
I wanna know where they got the 5/sintheta from though :(
dan815
  • dan815
|dw:1370927027427:dw|
dan815
  • dan815
@primeralph solve this
primeralph
  • primeralph
pi/4 is the angle or length?
primeralph
  • primeralph
want it in polar or cartesian?
anonymous
  • anonymous
All polar
dan815
  • dan815
|dw:1370928051972:dw|
dan815
  • dan815
nvm i got it!
primeralph
  • primeralph
|dw:1370927987796:dw|
primeralph
  • primeralph
no the lower bound for r is 5 not 0
dan815
  • dan815
nono i got it!! it makes sense now
primeralph
  • primeralph
why is the integrand r^2 cos(theta)?
primeralph
  • primeralph
Okay.
dan815
  • dan815
x=rcostheta, dxdy=rdrd@
anonymous
  • anonymous
This makes sense http://gyazo.com/548124189e808160e91afd23a3047117.png
anonymous
  • anonymous
|dw:1370928448061:dw|
dan815
  • dan815
in polar ofcourse lol..
dan815
  • dan815
|dw:1370928468512:dw|
anonymous
  • anonymous
|dw:1370928488372:dw|
anonymous
  • anonymous
|dw:1370928578606:dw|
anonymous
  • anonymous
Am I right? :D
dan815
  • dan815
set it up in polar
dan815
  • dan815
as u know for your last integral, y was constant and u cud find the change in r with respect to y and theta now do it with x
dan815
  • dan815
|dw:1370928611133:dw|
anonymous
  • anonymous
I'll create 1 more I want you to walk me through :)
dan815
  • dan815
ok ill try

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