DLS
  • DLS
Two small balls having same charge and mass of same vertical line are at height h and H (h
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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yrelhan4
  • yrelhan4
@Mashy
DLS
  • DLS
he doesn't come online now -.-
DLS
  • DLS
wth how did he come online ? co-incident?

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More answers

anonymous
  • anonymous
lol
anonymous
  • anonymous
i dont get the question at all :-/
DLS
  • DLS
what didn't you get?? :O
yrelhan4
  • yrelhan4
*fist bump* :)
anonymous
  • anonymous
it is thrown horizontally?!
anonymous
  • anonymous
|dw:1370950951843:dw|
DLS
  • DLS
correct
anonymous
  • anonymous
This looks a little complecated because, the acceleration of the charges are not constant right?!
DLS
  • DLS
Hint:this has to be solved using centre of mass concept :D
anonymous
  • anonymous
aha.. ofcourse.. now its very simple :D
DLS
  • DLS
??
anonymous
  • anonymous
The center of mass will act like a normal projectile.. !!
anonymous
  • anonymous
Since.. the charges don't experience any force in the x direction, when the centre of mass has reached the distance "d" from the vertical line, it would mean, that the first mass has hit the ground
anonymous
  • anonymous
wait.. lemme solve... check if my answer is right
DLS
  • DLS
sure
yrelhan4
  • yrelhan4
haha. why dont you solve it too @DLS ? :P
DLS
  • DLS
..
yrelhan4
  • yrelhan4
:3
yrelhan4
  • yrelhan4
chalo mai chala.
DLS
  • DLS
bulaya kisne tha :3
yrelhan4
  • yrelhan4
hmm ..l.
DLS
  • DLS
:D
DLS
  • DLS
yuhuuuuuuu @Mashy
anonymous
  • anonymous
is it \[h + H - \frac{gd^2}{u^2} ?\]
DLS
  • DLS
epic :O Teach me master!!
anonymous
  • anonymous
its easy.. i was drinking coffee :P.. rack your brains.. i have to leave for home now.. once i reach home ll draw and show ok
DLS
  • DLS
drop a better hint :/
anonymous
  • anonymous
the CM at all times is exactly in between the two masses, and the CM will move like an ordinary projectile.. thats your hint/... see you later
shubhamsrg
  • shubhamsrg
I think cons. of energy should help ?
DLS
  • DLS
\[\Large x=d-\frac{kq^2}{mg(H+h)+\mu^2+\frac{kq^2}{H-h}}\] @shubhamsrg ye ata hai apki eqn se :O
shubhamsrg
  • shubhamsrg
ye sahi nahi hai? :|
DLS
  • DLS
pata nahi mujhe >.<
shubhamsrg
  • shubhamsrg
tumne to bola tumhare paas ans hai ?
DLS
  • DLS
ans mashy ne thoda upar likha hai ..dekho
shubhamsrg
  • shubhamsrg
hmm,, RHS me thora modify karke dekho RHS me KE add kar do 1/2 m(2gh) + 1/2 m(2gH)
shubhamsrg
  • shubhamsrg
mere method se to par last me q ayega :/
DLS
  • DLS
CM.........................
shubhamsrg
  • shubhamsrg
mere method me kya flaw ho raha hai >.<
DLS
  • DLS
mai iss stage me bilkul nahi hoon ki tumhe bta saku ye
shubhamsrg
  • shubhamsrg
:/ @yrelhan4 of course..
yrelhan4
  • yrelhan4
lol. :/
yrelhan4
  • yrelhan4
yaar mera kal license banna hai to thoda sa uske liye padh rha hun. aur.. and match dekh rha hun. WI 182-9 :D
shubhamsrg
  • shubhamsrg
sir jadeja 5 wicket :")
yrelhan4
  • yrelhan4
sahi hai yr jadeja.
shubhamsrg
  • shubhamsrg
hmm, jabse use mock karna shuru kiya hai tabhi se acha khelna shuru kar diya :O
yrelhan4
  • yrelhan4
lol. koi mujhe bhi mock karna shuru karo. :P
shubhamsrg
  • shubhamsrg
kisi ki aukat hi nahi :)
yrelhan4
  • yrelhan4
hmm. :/ hua question @DLS ? :P
DLS
  • DLS
bye
shubhamsrg
  • shubhamsrg
hmm,, last me KE wala concept fail ho jayega kyunki waha newton's 3rd eqn nahi valid hoga.. hence cons of energy fail .. yo !!
anonymous
  • anonymous
There.. i have worked it out!!
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