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vknight33
Group Title
Consider the following algorithm.
x ← 1
for
i is in {1, 2, 3, 4}
do
for
j is in {1, 2, 3}
do
x ← x + x
for
k is in {1, 2, 3, 4, 5, 6}
do
x ← x + 1
x ← x + 5
Count the number of + operations done by this algorithm.
 one year ago
 one year ago
vknight33 Group Title
Consider the following algorithm. x ← 1 for i is in {1, 2, 3, 4} do for j is in {1, 2, 3} do x ← x + x for k is in {1, 2, 3, 4, 5, 6} do x ← x + 1 x ← x + 5 Count the number of + operations done by this algorithm.
 one year ago
 one year ago

This Question is Open

chris00 Group TitleBest ResponseYou've already chosen the best response.0
not my style of question. haha
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
it looks like some type of for/next looping but the syntax is hard to parse
 one year ago

vknight33 Group TitleBest ResponseYou've already chosen the best response.0
Its suppose to be discrete mathematics. I am not a math person at all.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
its countable ... but the syntax/notation is hard to read thru. without knowing what the format is trying to convey its difficult to understand the process that is being described
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
was this a write up or did you copy/paste it?
 one year ago

vknight33 Group TitleBest ResponseYou've already chosen the best response.0
I will do a screenshot and paste it here hang on
 one year ago

vknight33 Group TitleBest ResponseYou've already chosen the best response.0
Here it is
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
hmm, im guessing it follows as such: x = 1 for i = 1 to 4 for j = 1 to 3; x=x+x for k = 1 to 6; x=x+1, x=x+5 4(3(1)+6(2)) operations is what it looks like to me
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
x=n [x = n+n x = (n+n)+(n+n) x = (n+n)+(n+n)+(n+n)+(n+n) = 8(n) ] [x = 8(n)+6] x = 1 x'= 8(1)+6 x'= 8(8(14)+6)+6 x'= 8(8(8(14)+6)+6)+6 x'= 8(8(8(8(14)+6)+6)+6)+6 x = 60854
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
pfft, i left the 14 in there ... should be a 1 :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
x = 7606 if its 1 to start with
 one year ago

vknight33 Group TitleBest ResponseYou've already chosen the best response.0
Is that the answer for "Count the number of + operations done by this algorithm."
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
of course not, i already surmised the results for that .... this was just an attempt to actually work the algorithm to see what the output would give us ...
 one year ago
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