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e.cociuba
Group Title
Solve each equation by undoing each operation:
2(x+4)^2  7= 0
 one year ago
 one year ago
e.cociuba Group Title
Solve each equation by undoing each operation: 2(x+4)^2  7= 0
 one year ago
 one year ago

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chris00 Group TitleBest ResponseYou've already chosen the best response.0
(a+b)^2=a^2+2ab+b^2
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
add, divide, sqrt, subtract
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
in order to solve for x, its best not to have a bunch of seperate terms of x
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Ok so this is where I am at: dw:1370954995424:dw
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
yep. divide both sides by 2 now.
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
i personally would do it a different way.
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Y divide by 2?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
becasue 2/2 = 1
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
and quadratic formula is not faster ....
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
haha ^ true
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
but wiser.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
dw:1370955168617:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
we are trying to unwrap the "x" ... its stuck inside alot of excess baggage
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Ok so this is where I am: dw:1370955243877:dw
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Is tht correct?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
so far so good, i would not try to decimate that sqrt(7/2) tho .. unless its asking for an approximation
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
leave it alone .... the fraction is not important
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Ok so this then? dw:1370955496977:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
\[x+4=\pm\sqrt{\frac{7}{2}}\] this is an EXACT value, so unless the solution is asking you to decimate it ... leave it as is
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
^ use that!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
now finish off that 4 that keeps tagging along
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Oh ok so it's: dw:1370955725448:dw Correct?
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Awesome! Thanks guys! I appreciate it! GBU! :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
\[x=\frac{8\pm\sqrt{14}}{2}\]is also acceptable i believe
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
OH QUADRATIC FORMULA! haha
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Thanks for being patient with me guys! I appreciate it ;)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.2
good luck
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Gracias :))
 one year ago

chris00 Group TitleBest ResponseYou've already chosen the best response.0
i'm going to hit the sack now. have fun with maths :) good luck
 one year ago

e.cociuba Group TitleBest ResponseYou've already chosen the best response.0
Thanks you for you help! :)
 one year ago
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