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e.cociuba

  • 2 years ago

Solve each equation by undoing each operation: 2(x+4)^2 - 7= 0

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  1. chris00
    • 2 years ago
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    (a+b)^2=a^2+2ab+b^2

  2. chris00
    • 2 years ago
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    try that

  3. amistre64
    • 2 years ago
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    add, divide, sqrt, subtract

  4. amistre64
    • 2 years ago
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    in order to solve for x, its best not to have a bunch of seperate terms of x

  5. e.cociuba
    • 2 years ago
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    Ok so this is where I am at: |dw:1370954995424:dw|

  6. chris00
    • 2 years ago
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    yep. divide both sides by 2 now.

  7. chris00
    • 2 years ago
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    i personally would do it a different way.

  8. e.cociuba
    • 2 years ago
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    Y divide by 2?

  9. amistre64
    • 2 years ago
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    becasue 2/2 = 1

  10. amistre64
    • 2 years ago
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    and quadratic formula is not faster ....

  11. chris00
    • 2 years ago
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    haha ^ true

  12. chris00
    • 2 years ago
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    but wiser.

  13. amistre64
    • 2 years ago
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    |dw:1370955168617:dw|

  14. amistre64
    • 2 years ago
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    we are trying to unwrap the "x" ... its stuck inside alot of excess baggage

  15. e.cociuba
    • 2 years ago
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    Ok so this is where I am: |dw:1370955243877:dw|

  16. e.cociuba
    • 2 years ago
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    Is tht correct?

  17. amistre64
    • 2 years ago
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    so far so good, i would not try to decimate that sqrt(7/2) tho .. unless its asking for an approximation

  18. amistre64
    • 2 years ago
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    leave it alone .... the fraction is not important

  19. e.cociuba
    • 2 years ago
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    Ok so this then? |dw:1370955496977:dw|

  20. amistre64
    • 2 years ago
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    \[x+4=\pm\sqrt{\frac{7}{2}}\] this is an EXACT value, so unless the solution is asking you to decimate it ... leave it as is

  21. chris00
    • 2 years ago
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    ^ use that!

  22. amistre64
    • 2 years ago
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    now finish off that 4 that keeps tagging along

  23. e.cociuba
    • 2 years ago
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    Oh ok so it's: |dw:1370955725448:dw| Correct?

  24. chris00
    • 2 years ago
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    sweet.

  25. amistre64
    • 2 years ago
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    correct

  26. e.cociuba
    • 2 years ago
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    Awesome! Thanks guys! I appreciate it! GBU! :)

  27. amistre64
    • 2 years ago
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    \[x=\frac{-8\pm\sqrt{14}}{2}\]is also acceptable i believe

  28. chris00
    • 2 years ago
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    OH QUADRATIC FORMULA! haha

  29. e.cociuba
    • 2 years ago
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    Thanks for being patient with me guys! I appreciate it ;)

  30. amistre64
    • 2 years ago
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    good luck

  31. e.cociuba
    • 2 years ago
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    Gracias :))

  32. chris00
    • 2 years ago
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    i'm going to hit the sack now. have fun with maths :) good luck

  33. e.cociuba
    • 2 years ago
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    Thanks you for you help! :)

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