e.cociuba
  • e.cociuba
Solve each equation by undoing each operation: 2(x+4)^2 - 7= 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
(a+b)^2=a^2+2ab+b^2
anonymous
  • anonymous
try that
amistre64
  • amistre64
add, divide, sqrt, subtract

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amistre64
  • amistre64
in order to solve for x, its best not to have a bunch of seperate terms of x
e.cociuba
  • e.cociuba
Ok so this is where I am at: |dw:1370954995424:dw|
anonymous
  • anonymous
yep. divide both sides by 2 now.
anonymous
  • anonymous
i personally would do it a different way.
e.cociuba
  • e.cociuba
Y divide by 2?
amistre64
  • amistre64
becasue 2/2 = 1
amistre64
  • amistre64
and quadratic formula is not faster ....
anonymous
  • anonymous
haha ^ true
anonymous
  • anonymous
but wiser.
amistre64
  • amistre64
|dw:1370955168617:dw|
amistre64
  • amistre64
we are trying to unwrap the "x" ... its stuck inside alot of excess baggage
e.cociuba
  • e.cociuba
Ok so this is where I am: |dw:1370955243877:dw|
e.cociuba
  • e.cociuba
Is tht correct?
amistre64
  • amistre64
so far so good, i would not try to decimate that sqrt(7/2) tho .. unless its asking for an approximation
amistre64
  • amistre64
leave it alone .... the fraction is not important
e.cociuba
  • e.cociuba
Ok so this then? |dw:1370955496977:dw|
amistre64
  • amistre64
\[x+4=\pm\sqrt{\frac{7}{2}}\] this is an EXACT value, so unless the solution is asking you to decimate it ... leave it as is
anonymous
  • anonymous
^ use that!
amistre64
  • amistre64
now finish off that 4 that keeps tagging along
e.cociuba
  • e.cociuba
Oh ok so it's: |dw:1370955725448:dw| Correct?
anonymous
  • anonymous
sweet.
amistre64
  • amistre64
correct
e.cociuba
  • e.cociuba
Awesome! Thanks guys! I appreciate it! GBU! :)
amistre64
  • amistre64
\[x=\frac{-8\pm\sqrt{14}}{2}\]is also acceptable i believe
anonymous
  • anonymous
OH QUADRATIC FORMULA! haha
e.cociuba
  • e.cociuba
Thanks for being patient with me guys! I appreciate it ;)
amistre64
  • amistre64
good luck
e.cociuba
  • e.cociuba
Gracias :))
anonymous
  • anonymous
i'm going to hit the sack now. have fun with maths :) good luck
e.cociuba
  • e.cociuba
Thanks you for you help! :)

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