anonymous
  • anonymous
Electric fields and electric potentials of spherical charge inside spherical conductor!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
So here is the approximate scheme of a figure and its E and V at different levels depending on R.
anonymous
  • anonymous
R=5cm, ρ=2μC/m3 R1=24cm , thickness of a conducting sphere is 12cm. ( R2=36cm)
anonymous
  • anonymous
E ( r > R2 ) = 9.42 / r2 (example) E (R1 < r < R2 ) =? E (R < r < R1 ) =? E (r < R ) =?

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anonymous
  • anonymous
V(r>R2) ─ V∞ =? \[V2= V(r>R2)| _{R _{b}}\] =? V(R < r < R1 ) ─ V(R1) =? V(r < R ) ─ V(R) =?
anonymous
  • anonymous
inside the conductor there can be no charge so electric field is zero.all charges are distributed in the surface and so electric potentials are same all off the inside off the conductor and egual to surface potential
anonymous
  • anonymous
what about the electric field inside the conducting sphere, there sure is a electric field. I'm stuck on this problem. it is a tricky one
anonymous
  • anonymous
inside the conducting sphere is there andy empty space you can show your question exactly
anonymous
  • anonymous
can you show your question exactly sorry
anonymous
  • anonymous
it is a problem with few questions and it is in spanish. i attached the image of a figure . have you seen it?
anonymous
  • anonymous
yes now ı have seen it and ı understand ı will doit in paper and ı will take a photo for you
anonymous
  • anonymous
appreciate it! hope i will undesrtand conductors better with your solutions. :)
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
ıf you cannot undesrtand anything you can ask
anonymous
  • anonymous
thank you ! i am going trhough the notes now!
anonymous
  • anonymous
looks legit !!! thank you for explanations too !!! wish i can give more than one medal
anonymous
  • anonymous
you are welcome.I just had a final exam about these so ı will be a profession about these:)

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