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DribleDaVaca19

  • one year ago

Which matrix equation can be used to solve the system? Will draw it.

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  1. DribleDaVaca19
    • one year ago
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    |dw:1370965723891:dw|

  2. amistre64
    • one year ago
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    Ax = b x = A^(-1) b might be one of the options

  3. amistre64
    • one year ago
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    they was nice enough to give you a determinant of 1 ... how sweet

  4. DribleDaVaca19
    • one year ago
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    i have 4 answers

  5. amistre64
    • one year ago
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    the answers might help us determine a suitable soluton process

  6. DribleDaVaca19
    • one year ago
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    |dw:1370966096557:dw|

  7. amistre64
    • one year ago
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    ax + by = n cx + cy = m matrix A = a b c d vector b = n m so yeah, they are looking for an inverse setup

  8. DribleDaVaca19
    • one year ago
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    |dw:1370966191827:dw|

  9. amistre64
    • one year ago
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    do you recall how to find the inverse of a 2x2 matrix?

  10. amistre64
    • one year ago
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    the shorcut involves a swap and some negations, youll also need a determinant

  11. DribleDaVaca19
    • one year ago
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    never mind I found it out, thx anyways

  12. amistre64
    • one year ago
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    \[\begin{pmatrix}a&b\\c&d\end{pmatrix}^{-1}=\begin{pmatrix}d/|A|&-b/|A|\\-c/|A|&a/|A|\end{pmatrix}\]

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