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anonymous
 2 years ago
Translate this problem to an equation and solve.
The width of a rectangle is 6 inches less than twice its length. Find the dimension of the rectangle if its area is 108 square inches. @johnweldon1993
anonymous
 2 years ago
Translate this problem to an equation and solve. The width of a rectangle is 6 inches less than twice its length. Find the dimension of the rectangle if its area is 108 square inches. @johnweldon1993

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0let length be l width= 2 * l  6 let width be w l * w = 108 I think you can solve this now

johnweldon1993
 2 years ago
Best ResponseYou've already chosen the best response.0Just as @sampatho2 has shown W = 2L  6 A = L x W We know area 108 = L x W We know W = 2L  6 so substitute that in for 'W' 108 = L x (2L  6) can you take it from here...?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0where are you facing the problem. You just need to solve the equation for l

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0but i still dont get it

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Let x be the length and y the width. Then : \[2x6=y\\xy=108\] So from the 2nd equation we have : \[x=\frac{108}{y}\] And from the 1st equation : \[2\frac{108}{y}6=y\] We multiply by y to get : \[2166y=y^2\] And then : \[y^2+6y216=0\] so : \[\Delta=364\times(216)=900\] So : \[y=\frac{6+\sqrt{900}}{2}=\frac{6+30}{2}=12 \text{ inches}\] And then : \[x=\frac{108}y=\frac{108}{12}=9 \text{ inches}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i dont get it still @johnweldon1993 @Noura11

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Tell me what didn't understand in my solution and I will try to explain it to you ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the whole thing tht u did its suppost to be like this type the answer in this from:6*7

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Can you explain more , please ?
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