anonymous
  • anonymous
How do you find the P value of a hypothesis test?
Statistics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
its the area of the tails ....
amistre64
  • amistre64
determine the z or t score using the Ha as the cutoff stat for Ho the P-value is just the area left in the tails
anonymous
  • anonymous
This is my particular problem: A survey of 1910 people who took trips revealed that 136 of them included a visit to a theme park. Based on those survery results, a management consultant claims that less than 8% of trips include a theme park visit. Test this claim using the alpha= .01 significance level. Assuming Ho, The z score is? The critical z score for declaring significance is? The P Value of the Hypothesis test is_____?

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amistre64
  • amistre64
are you using a ti83, stat program, or just tables in the book?
amistre64
  • amistre64
|dw:1370969246279:dw|
anonymous
  • anonymous
I found the z score to be -1.4168...then the critical z score using norm.s.inv(.99) on excel to be 2.32...but I do nt know how to find the p value...would I need to find the z score for .08 and use that value into norm.s.dist(z value, cumulative)? that is what I think to do...but I don't know how to find the z value with P (x<.08)
anonymous
  • anonymous
we have been using excel..wow I am so glad I found this site, I have been searching for a free help site and had no luck
amistre64
  • amistre64
1910*.08 = 153 use 153 is your test value
amistre64
  • amistre64
since there is no standard deviation given, should we do a t stat, or a z stat? sample size seems well over 30 to me
anonymous
  • anonymous
what is a t stat?
anonymous
  • anonymous
I believe so...you mean z score?
amistre64
  • amistre64
its similar to a zscore stat, but uses a t distribution as opposed to a normal distribution .... its used for unknown standard deviations
dumbcow
  • dumbcow
@ViennaJade , Excel gives pvalue of .078 for z-score of -1.4168 "NORMSDIST(-1.4168)"
anonymous
  • anonymous
hmmm dumbcow let me try that
anonymous
  • anonymous
admiter I found the standard deviation by hand
amistre64
  • amistre64
136/1910 = .0712 as a "mean" this is less then 8% of the sample size already so i don think the score of 8% will be negative
anonymous
  • anonymous
I just checked dumbcow's answer and it was right
anonymous
  • anonymous
now I'm not sure I remember why his answer is right though...
amistre64
  • amistre64
\[\Large\frac{136}{1910}\pm Z_{.01}\left( \frac{\frac{136}{1910}\frac{1774}{1910}}{\sqrt{1910}} \right)\].01 in one tail is .02 in both tails,relates to a confidence interval of 98%, z=2.33 a confidence interval of 98% is \[\Large .0712\pm 2.33\frac{(.0712)(.9288)}{\sqrt{1910}}\] cows answer was correct, thats nice :)
amistre64
  • amistre64
opps, forgot to sqrt the whole thing
anonymous
  • anonymous
why are you finding the confidence interval? I'm confused
amistre64
  • amistre64
so an interval of .057 to infinity .... just trying to recall some stuff. how would you determine the test statistic for less then 8%?
anonymous
  • anonymous
I would want to use the z score formula , plug in 153/1910-.08 all over the standrd dev of .006208
anonymous
  • anonymous
and then use excel =norm.s.dist(the z score)
amistre64
  • amistre64
.08 - 153/1910 of course the only differnce is a sign
anonymous
  • anonymous
amistre thank you so much for helping me...and dumbow...do you get paid for this?
dumbcow
  • dumbcow
http://en.wikipedia.org/wiki/Statistical_hypothesis_testing#Common_test_statistics this problem is a 1-proportion z test right? \[z = \frac{.08 - \frac{136}{1910}}{\sqrt{\frac{136}{1910}(1-\frac{136}{1910})}}\sqrt{1910}\]
anonymous
  • anonymous
dumbcow I have no idea what that equation is...we were taught that z score of p hat= p hat-Ho/stdev
dumbcow
  • dumbcow
how are you finding std dev?
dumbcow
  • dumbcow
sqrt{n*p*(1-p)}
anonymous
  • anonymous
I don't think it's 1-proportion because they want less than .08
anonymous
  • anonymous
stdev of p hat= sqrt(p*q/n)
anonymous
  • anonymous
p is .08, q is .92
anonymous
  • anonymous
n is 1910
dumbcow
  • dumbcow
oh ok, well in that case you already did everything and didn't need any help :)
anonymous
  • anonymous
I still didn't get how you used the z score I found and used that to find the p(x<.08)? sorry..
dumbcow
  • dumbcow
|dw:1370971511146:dw| the p-value is the probability of being "left" of z-score on the bell curve the excel function "normSDist" will tell you the area "left" of a given z-score
dumbcow
  • dumbcow
if p-value < .01 , reject H0 otherwise Fail to reject H0
anonymous
  • anonymous
I think I get it. Thank you so much Amistre and dumbcow! :))
dumbcow
  • dumbcow
yw

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