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its the area of the tails ....

are you using a ti83, stat program, or just tables in the book?

|dw:1370969246279:dw|

1910*.08 = 153
use 153 is your test value

what is a t stat?

I believe so...you mean z score?

@ViennaJade , Excel gives pvalue of .078 for z-score of -1.4168
"NORMSDIST(-1.4168)"

hmmm dumbcow let me try that

admiter I found the standard deviation by hand

I just checked dumbcow's answer and it was right

now I'm not sure I remember why his answer is right though...

opps, forgot to sqrt the whole thing

why are you finding the confidence interval? I'm confused

I would want to use the z score formula , plug in 153/1910-.08 all over the standrd dev of .006208

and then use excel =norm.s.dist(the z score)

.08 - 153/1910 of course the only differnce is a sign

amistre thank you so much for helping me...and dumbow...do you get paid for this?

dumbcow I have no idea what that equation is...we were taught that z score of p hat= p hat-Ho/stdev

how are you finding std dev?

sqrt{n*p*(1-p)}

I don't think it's 1-proportion because they want less than .08

stdev of p hat= sqrt(p*q/n)

p is .08, q is .92

n is 1910

oh ok, well in that case you already did everything and didn't need any help :)

I still didn't get how you used the z score I found and used that to find the p(x<.08)? sorry..

if p-value < .01 , reject H0
otherwise Fail to reject H0

I think I get it. Thank you so much Amistre and dumbcow! :))

yw