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amistre64Best ResponseYou've already chosen the best response.1
its the area of the tails ....
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
determine the z or t score using the Ha as the cutoff stat for Ho the Pvalue is just the area left in the tails
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
This is my particular problem: A survey of 1910 people who took trips revealed that 136 of them included a visit to a theme park. Based on those survery results, a management consultant claims that less than 8% of trips include a theme park visit. Test this claim using the alpha= .01 significance level. Assuming Ho, The z score is? The critical z score for declaring significance is? The P Value of the Hypothesis test is_____?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
are you using a ti83, stat program, or just tables in the book?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
dw:1370969246279:dw
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I found the z score to be 1.4168...then the critical z score using norm.s.inv(.99) on excel to be 2.32...but I do nt know how to find the p value...would I need to find the z score for .08 and use that value into norm.s.dist(z value, cumulative)? that is what I think to do...but I don't know how to find the z value with P (x<.08)
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
we have been using excel..wow I am so glad I found this site, I have been searching for a free help site and had no luck
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
1910*.08 = 153 use 153 is your test value
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
since there is no standard deviation given, should we do a t stat, or a z stat? sample size seems well over 30 to me
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I believe so...you mean z score?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
its similar to a zscore stat, but uses a t distribution as opposed to a normal distribution .... its used for unknown standard deviations
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
@ViennaJade , Excel gives pvalue of .078 for zscore of 1.4168 "NORMSDIST(1.4168)"
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
hmmm dumbcow let me try that
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
admiter I found the standard deviation by hand
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
136/1910 = .0712 as a "mean" this is less then 8% of the sample size already so i don think the score of 8% will be negative
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I just checked dumbcow's answer and it was right
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
now I'm not sure I remember why his answer is right though...
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\Large\frac{136}{1910}\pm Z_{.01}\left( \frac{\frac{136}{1910}\frac{1774}{1910}}{\sqrt{1910}} \right)\].01 in one tail is .02 in both tails,relates to a confidence interval of 98%, z=2.33 a confidence interval of 98% is \[\Large .0712\pm 2.33\frac{(.0712)(.9288)}{\sqrt{1910}}\] cows answer was correct, thats nice :)
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
opps, forgot to sqrt the whole thing
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
why are you finding the confidence interval? I'm confused
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
so an interval of .057 to infinity .... just trying to recall some stuff. how would you determine the test statistic for less then 8%?
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I would want to use the z score formula , plug in 153/1910.08 all over the standrd dev of .006208
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
and then use excel =norm.s.dist(the z score)
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
.08  153/1910 of course the only differnce is a sign
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
amistre thank you so much for helping me...and dumbow...do you get paid for this?
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
http://en.wikipedia.org/wiki/Statistical_hypothesis_testing#Common_test_statistics this problem is a 1proportion z test right? \[z = \frac{.08  \frac{136}{1910}}{\sqrt{\frac{136}{1910}(1\frac{136}{1910})}}\sqrt{1910}\]
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
dumbcow I have no idea what that equation is...we were taught that z score of p hat= p hatHo/stdev
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
how are you finding std dev?
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I don't think it's 1proportion because they want less than .08
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
stdev of p hat= sqrt(p*q/n)
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
p is .08, q is .92
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
oh ok, well in that case you already did everything and didn't need any help :)
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I still didn't get how you used the z score I found and used that to find the p(x<.08)? sorry..
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
dw:1370971511146:dw the pvalue is the probability of being "left" of zscore on the bell curve the excel function "normSDist" will tell you the area "left" of a given zscore
 10 months ago

dumbcowBest ResponseYou've already chosen the best response.2
if pvalue < .01 , reject H0 otherwise Fail to reject H0
 10 months ago

ViennaJadeBest ResponseYou've already chosen the best response.0
I think I get it. Thank you so much Amistre and dumbcow! :))
 10 months ago
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