anonymous
  • anonymous
Approximately 15% of peole are left-handed. If two people are selected at random, what is the probability of the following events? P(At least one is right-handed)? Is this correct? 1-P(none are RH) so..1-P(LH and LH) 1-(.85)(.85) =1-.7225 =.2775...is this correct?
Statistics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
should we assume that people can either be left or right handed, but not both?
anonymous
  • anonymous
well I guess it's possible to be both
anonymous
  • anonymous
but I've never had a question ask me that...

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amistre64
  • amistre64
since no stats are given as to ambidextrous peoples ... P(l) = .15, P(r) = .85 at least one is P(l) lr + ll
amistre64
  • amistre64
at least one is right handed that is .... lr + rr
anonymous
  • anonymous
Thank you! that makes sense.
amistre64
  • amistre64
the possible ways to choose 2 people are: ll .15*.15 lr .15*.85 rl .85*.15 rr .85*.85 at least 1 r in it is: lr + rl + rr does that sound right?
amistre64
  • amistre64
1 - ll :) .9775
anonymous
  • anonymous
yes it does. makes so much more sense. Thank you!
anonymous
  • anonymous
wait so is the answer .85?
amistre64
  • amistre64
ll+lr+rl+rr = 1 lr+rl+rr = 1 - ll since l = .15 ... 1 - .15^2 = .9775
anonymous
  • anonymous
oh sorry I forgot the one part..thank you!

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