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anonymous
 2 years ago
Approximately 15% of peole are lefthanded. If two people are selected at random, what is the probability of the following events?
P(At least one is righthanded)?
Is this correct?
1P(none are RH)
so..1P(LH and LH)
1(.85)(.85)
=1.7225
=.2775...is this correct?
anonymous
 2 years ago
Approximately 15% of peole are lefthanded. If two people are selected at random, what is the probability of the following events? P(At least one is righthanded)? Is this correct? 1P(none are RH) so..1P(LH and LH) 1(.85)(.85) =1.7225 =.2775...is this correct?

This Question is Closed

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1should we assume that people can either be left or right handed, but not both?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well I guess it's possible to be both

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0but I've never had a question ask me that...

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1since no stats are given as to ambidextrous peoples ... P(l) = .15, P(r) = .85 at least one is P(l) lr + ll

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1at least one is right handed that is .... lr + rr

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you! that makes sense.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the possible ways to choose 2 people are: ll .15*.15 lr .15*.85 rl .85*.15 rr .85*.85 at least 1 r in it is: lr + rl + rr does that sound right?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes it does. makes so much more sense. Thank you!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0wait so is the answer .85?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1ll+lr+rl+rr = 1 lr+rl+rr = 1  ll since l = .15 ... 1  .15^2 = .9775

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh sorry I forgot the one part..thank you!
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