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Approximately 15% of peole are left-handed. If two people are selected at random, what is the probability of the following events? P(At least one is right-handed)? Is this correct? 1-P(none are RH) so..1-P(LH and LH) 1-(.85)(.85) =1-.7225 this correct?

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should we assume that people can either be left or right handed, but not both?
well I guess it's possible to be both
but I've never had a question ask me that...

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since no stats are given as to ambidextrous peoples ... P(l) = .15, P(r) = .85 at least one is P(l) lr + ll
at least one is right handed that is .... lr + rr
Thank you! that makes sense.
the possible ways to choose 2 people are: ll .15*.15 lr .15*.85 rl .85*.15 rr .85*.85 at least 1 r in it is: lr + rl + rr does that sound right?
1 - ll :) .9775
yes it does. makes so much more sense. Thank you!
wait so is the answer .85?
ll+lr+rl+rr = 1 lr+rl+rr = 1 - ll since l = .15 ... 1 - .15^2 = .9775
oh sorry I forgot the one part..thank you!

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