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baybay88
Group Title
Help! what are the ratios for sin X and cos X?
drawing below
 one year ago
 one year ago
baybay88 Group Title
Help! what are the ratios for sin X and cos X? drawing below
 one year ago
 one year ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
sin = over/hyp cos = next.to/hyp
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
dw:1370976541873:dw
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
so how do i write it with those numbers?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
memory tricks may be: theres a SIGN, OVER there COSy up NEXT.TO someone you like
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
haha thats good!! i forgot which one was the hyp though...
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
dw:1370976658919:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
hyp is the side that is neither over or next.to :) its the slanted part of the rt tri
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
oh so then to 5\[5 \over 119?\]
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
sorry math isnt the best for me lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
if we observe the X angle: over = sqrt(119) next.to = 5 that leaves hyp=12 sin X = over/hyp cos X = next.to/hyp its just a matter of filling in the proper parts
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
ok so then it would be 119/12 for sin and 5/12 for cos?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
yes, but dont forget to notate that 119 properly: \(\sqrt{119}\)
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
ok so if i did it write then the sin would be 130.904?
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
and cos would be 0.416?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
your cosine is fine you hit some wrong buttons on your calculator for the sin tho
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
oh really?oh yeah I did that wrong. Thank you!!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
a good dbl chk is that sin^2 + cos^2 = 1 sin^2 + (5/12)^2 = 1 sin^2 + 25/144 = 1 sin^2 = 1  25/144 sin^2 = 119/144 sin = sqrt(119)/12 but then youd still ahv eto hit the right buttons :)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
good luck
 one year ago

baybay88 Group TitleBest ResponseYou've already chosen the best response.0
thank you!
 one year ago
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