Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

baybay88

  • 2 years ago

Help! what are the ratios for sin X and cos X? drawing below

  • This Question is Closed
  1. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sin = over/hyp cos = next.to/hyp

  2. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1370976541873:dw|

  3. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so how do i write it with those numbers?

  4. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    memory tricks may be: theres a SIGN, OVER there COSy up NEXT.TO someone you like

  5. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha thats good!! i forgot which one was the hyp though...

  6. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1370976658919:dw|

  7. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hyp is the side that is neither over or next.to :) its the slanted part of the rt tri

  8. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh so then to 5\[5 \over 119?\]

  9. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry math isnt the best for me lol

  10. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    if we observe the X angle: over = sqrt(119) next.to = 5 that leaves hyp=12 sin X = over/hyp cos X = next.to/hyp its just a matter of filling in the proper parts

  11. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so then it would be 119/12 for sin and 5/12 for cos?

  12. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, but dont forget to notate that 119 properly: \(\sqrt{119}\)

  13. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so if i did it write then the sin would be 130.904?

  14. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    *right

  15. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and cos would be 0.416?

  16. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    your cosine is fine you hit some wrong buttons on your calculator for the sin tho

  17. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh really?oh yeah I did that wrong. Thank you!!

  18. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    a good dbl chk is that sin^2 + cos^2 = 1 sin^2 + (5/12)^2 = 1 sin^2 + 25/144 = 1 sin^2 = 1 - 25/144 sin^2 = 119/144 sin = sqrt(119)/12 but then youd still ahv eto hit the right buttons :)

  19. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    good luck

  20. baybay88
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you!

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy