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Help! what are the ratios for sin X and cos X? drawing below

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sin = over/hyp cos =
so how do i write it with those numbers?

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Other answers:

memory tricks may be: theres a SIGN, OVER there COSy up NEXT.TO someone you like
haha thats good!! i forgot which one was the hyp though...
hyp is the side that is neither over or :) its the slanted part of the rt tri
oh so then to 5\[5 \over 119?\]
sorry math isnt the best for me lol
if we observe the X angle: over = sqrt(119) = 5 that leaves hyp=12 sin X = over/hyp cos X = its just a matter of filling in the proper parts
ok so then it would be 119/12 for sin and 5/12 for cos?
yes, but dont forget to notate that 119 properly: \(\sqrt{119}\)
ok so if i did it write then the sin would be 130.904?
and cos would be 0.416?
your cosine is fine you hit some wrong buttons on your calculator for the sin tho
oh really?oh yeah I did that wrong. Thank you!!
a good dbl chk is that sin^2 + cos^2 = 1 sin^2 + (5/12)^2 = 1 sin^2 + 25/144 = 1 sin^2 = 1 - 25/144 sin^2 = 119/144 sin = sqrt(119)/12 but then youd still ahv eto hit the right buttons :)
good luck
thank you!

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