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Help! what are the ratios for sin X and cos X? drawing below

Mathematics
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sin = over/hyp cos = next.to/hyp
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so how do i write it with those numbers?

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Other answers:

memory tricks may be: theres a SIGN, OVER there COSy up NEXT.TO someone you like
haha thats good!! i forgot which one was the hyp though...
|dw:1370976658919:dw|
hyp is the side that is neither over or next.to :) its the slanted part of the rt tri
oh so then to 5\[5 \over 119?\]
sorry math isnt the best for me lol
if we observe the X angle: over = sqrt(119) next.to = 5 that leaves hyp=12 sin X = over/hyp cos X = next.to/hyp its just a matter of filling in the proper parts
ok so then it would be 119/12 for sin and 5/12 for cos?
yes, but dont forget to notate that 119 properly: \(\sqrt{119}\)
ok so if i did it write then the sin would be 130.904?
*right
and cos would be 0.416?
your cosine is fine you hit some wrong buttons on your calculator for the sin tho
https://www.google.com/search?q=sqrt(119)%2F12&oq=sqrt(119)%2F12&aqs=chrome.0.57j0j62l3.4946j0&sourceid=chrome&ie=UTF-8
oh really?oh yeah I did that wrong. Thank you!!
a good dbl chk is that sin^2 + cos^2 = 1 sin^2 + (5/12)^2 = 1 sin^2 + 25/144 = 1 sin^2 = 1 - 25/144 sin^2 = 119/144 sin = sqrt(119)/12 but then youd still ahv eto hit the right buttons :)
good luck
thank you!

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