anonymous
  • anonymous
find the limit as x approaches infinity of x^2+x/3-x thanks
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
An explanation of how to solve limits approaching infinity would be helpful. Thanks :)
anonymous
  • anonymous
l'hopital's rule
anonymous
  • anonymous
so the answer would just be 2x

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jdoe0001
  • jdoe0001
ahemm, something tells me joshy12 is not doing l'hopital yet if at all
anonymous
  • anonymous
Do you know l'hopital's rule joselin?
anonymous
  • anonymous
jdoe, actaully i do
dumbcow
  • dumbcow
there is no horizontal asymptote but there is a limit , its just that it goes to neg infinity
jdoe0001
  • jdoe0001
@joselin12 ohh, okie dokie
anonymous
  • anonymous
Activate l'hopital's rule and plug in infinity and tell me what you get
anonymous
  • anonymous
\[\frac{( x^2-x)' }{(3-x)' }=\frac{ 2x-1 }{ -1 }=-2\infty-1= -\infty\]
anonymous
  • anonymous
When I do l'hopital's rule i get 2x..
anonymous
  • anonymous
You can't divide by parts! Look at how I did my operations
anonymous
  • anonymous
Isn't it suppose to be 2x+1 ?
anonymous
  • anonymous
I guess so, but it's irrelevant
anonymous
  • anonymous
-2x+1
anonymous
  • anonymous
|dw:1370988284679:dw|
anonymous
  • anonymous
Great, so we got -2x+1 which comes out to be -inf
anonymous
  • anonymous
okay, i get it now :) ty
anonymous
  • anonymous
Medal? :D
anonymous
  • anonymous
hahahaha fine :)

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