QUIZ TIME : RULES :
The questions will be not hard, they all will be easy. The one who answers first and picks it right gets +4 marks, the second one should NOT give answer directly, he must write a little hint for the solution and if it is correct then he will get +2 marks.
NEGATIVE MARKING = (-1)
So, friends are you ready?

- mathslover

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- katieb

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- anonymous

Ready :)

- anonymous

Ready!

- thomaster

ok last one :D

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## More answers

- mathslover

OK guys sorry, my net is slow. but its okay now.

- mathslover

Point which is equidistant from : vertices of triangle and sides of triangle ...
(There are two points, name them both)
Best of luck

- anonymous

circumcenter

- anonymous

Vertices - circuncenter and the other incenter

- anonymous

Vertices - circumcenter and sides incenter. there are the exincenter too in the sides.

- terenzreignz

No idea. I lose flair when it's no longer computation :D

- thomaster

i guess i'll have to change my name to mathshater when that option becomes available :P

- anonymous

|dw:1371001459531:dw|

- anonymous

Circumcenter, incenter and excenter.

- mathslover

future math professor, there r two points :)

- anonymous

W000000000000000000T

- mathslover

I will not say now, who is correct or who is wrong. I will wait for one more to answer. Come on friends, you all still have a chance to get +2.

- terenzreignz

You can't hint when it's not computation,@mathslover

- anonymous

Too bad

- mathslover

Yep. So @zairhenrique got +4 and @FutureMathProfessor got +2

- Jhannybean

Lol,. illuminati....!

- anonymous

LOOOOOOOOOOOOOOOOOOOL

- anonymous

You have the circumcenter that is equidistant from the vertices and the incenter and the excenter that is equidistant from the sides, considering the support lines of the sides.

- mathslover

POINTS : @FutureMathProfessor : 12
@terenzreignz : 8
@zairhenrique : 8
@giolefpatceid : 3
@thomaster : 2

- mathslover

Ok guys, be ready with a pen and a paper now.

- mathslover

Ready?

- anonymous

Wait

- thomaster

y

- terenzreignz

too lazy to get up and get one :D

- anonymous

Ready.

- mathslover

Trust me, you will need both, pen and paper. Have faith on me :P :D

- Jhannybean

The moment you're ready to aswer a question and you're being tagged EVERYWHERE

- anonymous

My internet are with problems. It's reconnecting all the time ;/

- mathslover

Only some good users can answer this. @Zarkon can do that, I am sure,.

- anonymous

But, i'm ready.

- anonymous

Kk I'm ready

- Jhannybean

LOL THANKS FOR HAVING FAITH IN US.

- anonymous

I'm having some troubles with my internet connection, ;/

- mathslover

Find the no. of solutions in positive integers of : \(3x^{10} - y^{10} = 1991\)
NOTE : this question is not easy, take time to solve it.

- mathslover

zair pm me then with answer .

- anonymous

integer solutions, solutions for y, ... ?

- terenzreignz

diophantine problem? pass :D

- mathslover

Sorry, question had a mistake : No. of integral solutions of \(3x^{10} - y^{10} = 1991\) =?

- thomaster

allright that's it for tonight xD
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╰━━━╯╰╯╱╰━━━╯╰━━━╯╰╯╱╰━━━╯╰╯

- Jhannybean

integral SOLUTIONS??/....

- mathslover

Bye thomaster :P , you have only 2 points in this quiz but still , good work.
Integral solutions - those who are integer and yes you have to find solutions for (x,y)

- anonymous

This question will take all day just move on

- mathslover

@amistre64 , try to solve it.

- anonymous

I think I have seen this question again. I don't remember though at what course

- anonymous

I think it was in a course on Algorithms

- mathslover

HINT : It involves simple maths...

- anonymous

I think there's no integer solutions... there is ?

- mathslover

Is this your sure answer?

- mathslover

GUYS : 5 minutes for u all more. I am getting bored now LOL

- anonymous

Yeah

- anonymous

i'm trying to demonstrate it rs

- anonymous

but, probably theres a solution...

- mathslover

Be sure.

- anonymous

no solutions.

- anonymous

It's Discrete Mathematics. I think you treat x and y like holes and you want to place a number of balls in them. And you are looking at the number of ways you can do that

- mathslover

You're right @zairhenrique (Congo)
+4 for you.
Any one else want to give solution or hint to get +2?

- anonymous

Because it's not a "function"

- mathslover

Points :
@zairhencrique : 12
@FutureMathProfessor : 10
@terenzreignz : 8
@giolefpatceid : 3
@thomaster : 2
(Nope @FutureMathProfessor )

- mathslover

Nope , there is algebra involved not combinatorics @giolefpatceid

- anonymous

I have 12 points you noob not 10!

- anonymous

xD

- mathslover

lol sorry, i have somewhat confusion here :D

- anonymous

xD

- mathslover

@zairhenrique : 12
@FutureMathProfessor : 12
@terenzreignz : 8
@giolefpatceid : 3
@thomaster : 2

- mathslover

Guys ready for next question?

- anonymous

Yeah fast

- mathslover

HERE :
if f(x) = |x-2| and g(x) = f(f(x) ) , then g'(-1) + g'(1) + g'(3) + g'(5) = ?
@satellite73 try it :P

- anonymous

8

- mathslover

@giolefpatceid , is 8 your answer?

- anonymous

yes

- anonymous

g'(x) = derivative of g(x) ?

- mathslover

Nope, -1 :(
And yes @zairhenrique

- Jhannybean

Can someone delete @Kittens4Mittens comment? That is so inappropriate.

- anonymous

It's ok, just wanted to take a risk, hehe!

- mathslover

@Kittens4Mittens behave yourself, its educational website, @satellite73 , please delete that comment.

- NoelGreco

Zero

- anonymous

zero

- mathslover

@NoelGreco +4 and @zairhenrique , +2 :)

- anonymous

my guess is zero

- anonymous

g(x) = ||x-2|-2|
g'(x) = ((x-2)|x-2|-2x+4)/(|x-2|||x-2|-2|)

- mathslover

Sure @satellite73 ?

- mathslover

@zairhenrique Good work

- mathslover

Guys: the correct answer is 0.
THE QUIZ ENDS ---------

- anonymous

no i am not sure of anything

- mathslover

@satellite73 You were correct :)

- terenzreignz

aww oh well, kudos, @zairhenrique :)

- mathslover

WINNER: @zairhenrique Congrats :)

- anonymous

Since the quiz is over I'm taking over! Come to my thread now

- mathslover

@FutureMathProfessor I will come to it in about 15 or 20 minutes....
Thanks everyone for participating in this quiz and making it educational as well as enjoyable.
Have a nice time :)

- anonymous

here is my question
adam and eve agree to meet by the apple tree between noon and 1, but but neither will wait more than 15 minutes for the other
if they both arrive uniformly at random between noon and 1, what is the probability they meet?

- anonymous

100% ?

- mathslover

@satellite73 Please give me 15 minutes, I will surely give it a try.

- terenzreignz

It's not like they had clocks back then XD
LOL jk

- mathslover

Yaaa @terenzreignz good :)

- anonymous

here is an easier one
smith and wesson alternately toss a coin
the first one to get heads wins
if smith tosses first, what is the probability he wins

- terenzreignz

2/3 ?

- anonymous

it is adam sandler and eve arden, apple tree is in central park
yes, \(\frac{2}{3}\)

- terenzreignz

yay ^.^
Too bad I'm terrible with probabilities :3

- GoldPhenoix

What's my points? :D

- anonymous

Who bumped this -.-

- mathslover

:P

- anonymous

=-D

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