mathslover
  • mathslover
QUIZ TIME : RULES : The questions will be not hard, they all will be easy. The one who answers first and picks it right gets +4 marks, the second one should NOT give answer directly, he must write a little hint for the solution and if it is correct then he will get +2 marks. NEGATIVE MARKING = (-1) So, friends are you ready?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Ready :)
anonymous
  • anonymous
Ready!
thomaster
  • thomaster
ok last one :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathslover
  • mathslover
OK guys sorry, my net is slow. but its okay now.
mathslover
  • mathslover
Point which is equidistant from : vertices of triangle and sides of triangle ... (There are two points, name them both) Best of luck
anonymous
  • anonymous
circumcenter
anonymous
  • anonymous
Vertices - circuncenter and the other incenter
anonymous
  • anonymous
Vertices - circumcenter and sides incenter. there are the exincenter too in the sides.
terenzreignz
  • terenzreignz
No idea. I lose flair when it's no longer computation :D
thomaster
  • thomaster
i guess i'll have to change my name to mathshater when that option becomes available :P
anonymous
  • anonymous
|dw:1371001459531:dw|
anonymous
  • anonymous
Circumcenter, incenter and excenter.
mathslover
  • mathslover
future math professor, there r two points :)
anonymous
  • anonymous
W000000000000000000T
mathslover
  • mathslover
I will not say now, who is correct or who is wrong. I will wait for one more to answer. Come on friends, you all still have a chance to get +2.
terenzreignz
  • terenzreignz
You can't hint when it's not computation,@mathslover
anonymous
  • anonymous
Too bad
mathslover
  • mathslover
Yep. So @zairhenrique got +4 and @FutureMathProfessor got +2
Jhannybean
  • Jhannybean
Lol,. illuminati....!
anonymous
  • anonymous
LOOOOOOOOOOOOOOOOOOOL
anonymous
  • anonymous
You have the circumcenter that is equidistant from the vertices and the incenter and the excenter that is equidistant from the sides, considering the support lines of the sides.
mathslover
  • mathslover
POINTS : @FutureMathProfessor : 12 @terenzreignz : 8 @zairhenrique : 8 @giolefpatceid : 3 @thomaster : 2
mathslover
  • mathslover
Ok guys, be ready with a pen and a paper now.
mathslover
  • mathslover
Ready?
anonymous
  • anonymous
Wait
thomaster
  • thomaster
y
terenzreignz
  • terenzreignz
too lazy to get up and get one :D
anonymous
  • anonymous
Ready.
mathslover
  • mathslover
Trust me, you will need both, pen and paper. Have faith on me :P :D
Jhannybean
  • Jhannybean
The moment you're ready to aswer a question and you're being tagged EVERYWHERE
anonymous
  • anonymous
My internet are with problems. It's reconnecting all the time ;/
mathslover
  • mathslover
Only some good users can answer this. @Zarkon can do that, I am sure,.
anonymous
  • anonymous
But, i'm ready.
anonymous
  • anonymous
Kk I'm ready
Jhannybean
  • Jhannybean
LOL THANKS FOR HAVING FAITH IN US.
anonymous
  • anonymous
I'm having some troubles with my internet connection, ;/
mathslover
  • mathslover
Find the no. of solutions in positive integers of : \(3x^{10} - y^{10} = 1991\) NOTE : this question is not easy, take time to solve it.
mathslover
  • mathslover
zair pm me then with answer .
anonymous
  • anonymous
integer solutions, solutions for y, ... ?
terenzreignz
  • terenzreignz
diophantine problem? pass :D
mathslover
  • mathslover
Sorry, question had a mistake : No. of integral solutions of \(3x^{10} - y^{10} = 1991\) =?
thomaster
  • thomaster
allright that's it for tonight xD ╭━━┳╮╱╱╭┳━━━╮╭━━┳╮╱╱╭┳━━━╮╭╮ ┃╭╮┃╰╮╭╯┃╭━━╯┃╭╮┃╰╮╭╯┃╭━━╯┃┃ ┃╰╯╰╮╰╯╭┫╰━━╮┃╰╯╰╮╰╯╭┫╰━━╮┃┃ ┃╭━╮┣╮╭╯┃╭━━╯┃╭━╮┣╮╭╯┃╭━━╯╰╯ ┃╰━╯┃┃┃╱┃╰━━╮┃╰━╯┃┃┃╱┃╰━━╮╭╮ ╰━━━╯╰╯╱╰━━━╯╰━━━╯╰╯╱╰━━━╯╰╯
Jhannybean
  • Jhannybean
integral SOLUTIONS??/....
mathslover
  • mathslover
Bye thomaster :P , you have only 2 points in this quiz but still , good work. Integral solutions - those who are integer and yes you have to find solutions for (x,y)
anonymous
  • anonymous
This question will take all day just move on
mathslover
  • mathslover
@amistre64 , try to solve it.
anonymous
  • anonymous
I think I have seen this question again. I don't remember though at what course
anonymous
  • anonymous
I think it was in a course on Algorithms
mathslover
  • mathslover
HINT : It involves simple maths...
anonymous
  • anonymous
I think there's no integer solutions... there is ?
mathslover
  • mathslover
Is this your sure answer?
mathslover
  • mathslover
GUYS : 5 minutes for u all more. I am getting bored now LOL
anonymous
  • anonymous
Yeah
anonymous
  • anonymous
i'm trying to demonstrate it rs
anonymous
  • anonymous
but, probably theres a solution...
mathslover
  • mathslover
Be sure.
anonymous
  • anonymous
no solutions.
anonymous
  • anonymous
It's Discrete Mathematics. I think you treat x and y like holes and you want to place a number of balls in them. And you are looking at the number of ways you can do that
mathslover
  • mathslover
You're right @zairhenrique (Congo) +4 for you. Any one else want to give solution or hint to get +2?
anonymous
  • anonymous
Because it's not a "function"
mathslover
  • mathslover
Points : @zairhencrique : 12 @FutureMathProfessor : 10 @terenzreignz : 8 @giolefpatceid : 3 @thomaster : 2 (Nope @FutureMathProfessor )
mathslover
  • mathslover
Nope , there is algebra involved not combinatorics @giolefpatceid
anonymous
  • anonymous
I have 12 points you noob not 10!
anonymous
  • anonymous
xD
mathslover
  • mathslover
lol sorry, i have somewhat confusion here :D
anonymous
  • anonymous
xD
mathslover
  • mathslover
@zairhenrique : 12 @FutureMathProfessor : 12 @terenzreignz : 8 @giolefpatceid : 3 @thomaster : 2
mathslover
  • mathslover
Guys ready for next question?
anonymous
  • anonymous
Yeah fast
mathslover
  • mathslover
HERE : if f(x) = |x-2| and g(x) = f(f(x) ) , then g'(-1) + g'(1) + g'(3) + g'(5) = ? @satellite73 try it :P
anonymous
  • anonymous
8
mathslover
  • mathslover
@giolefpatceid , is 8 your answer?
anonymous
  • anonymous
yes
anonymous
  • anonymous
g'(x) = derivative of g(x) ?
mathslover
  • mathslover
Nope, -1 :( And yes @zairhenrique
Jhannybean
  • Jhannybean
Can someone delete @Kittens4Mittens comment? That is so inappropriate.
anonymous
  • anonymous
It's ok, just wanted to take a risk, hehe!
mathslover
  • mathslover
@Kittens4Mittens behave yourself, its educational website, @satellite73 , please delete that comment.
NoelGreco
  • NoelGreco
Zero
anonymous
  • anonymous
zero
mathslover
  • mathslover
@NoelGreco +4 and @zairhenrique , +2 :)
anonymous
  • anonymous
my guess is zero
anonymous
  • anonymous
g(x) = ||x-2|-2| g'(x) = ((x-2)|x-2|-2x+4)/(|x-2|||x-2|-2|)
mathslover
  • mathslover
Sure @satellite73 ?
mathslover
  • mathslover
@zairhenrique Good work
mathslover
  • mathslover
Guys: the correct answer is 0. THE QUIZ ENDS ---------
anonymous
  • anonymous
no i am not sure of anything
mathslover
  • mathslover
@satellite73 You were correct :)
terenzreignz
  • terenzreignz
aww oh well, kudos, @zairhenrique :)
mathslover
  • mathslover
WINNER: @zairhenrique Congrats :)
anonymous
  • anonymous
Since the quiz is over I'm taking over! Come to my thread now
mathslover
  • mathslover
@FutureMathProfessor I will come to it in about 15 or 20 minutes.... Thanks everyone for participating in this quiz and making it educational as well as enjoyable. Have a nice time :)
anonymous
  • anonymous
here is my question adam and eve agree to meet by the apple tree between noon and 1, but but neither will wait more than 15 minutes for the other if they both arrive uniformly at random between noon and 1, what is the probability they meet?
anonymous
  • anonymous
100% ?
mathslover
  • mathslover
@satellite73 Please give me 15 minutes, I will surely give it a try.
terenzreignz
  • terenzreignz
It's not like they had clocks back then XD LOL jk
mathslover
  • mathslover
Yaaa @terenzreignz good :)
anonymous
  • anonymous
here is an easier one smith and wesson alternately toss a coin the first one to get heads wins if smith tosses first, what is the probability he wins
terenzreignz
  • terenzreignz
2/3 ?
anonymous
  • anonymous
it is adam sandler and eve arden, apple tree is in central park yes, \(\frac{2}{3}\)
terenzreignz
  • terenzreignz
yay ^.^ Too bad I'm terrible with probabilities :3
GoldPhenoix
  • GoldPhenoix
What's my points? :D
anonymous
  • anonymous
Who bumped this -.-
mathslover
  • mathslover
:P
anonymous
  • anonymous
=-D

Looking for something else?

Not the answer you are looking for? Search for more explanations.