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okay, what's the vertex here?
remember, if you see a form y = a(x - h)² + k then the vertex is (h,k)
THIS IS A PRETEST I DONT KNOW HOW TO DO THIS
Calm down, I just told you how to do it :) Look at your equation and identify which values correspond to h and k. y = a( x - h )² + k
-7 AND 6 CORRESPOND
But that would mean h = -7 and k = 6?
Which would make your equation y = a ( x - (-7) )² + 6 y = a ( x + 7 )² +6 Which is not your equation, is it? :)
OK SO IS IT MAX. OR MIN.
First, what's your vertex? (and easy on the caps lock there, mate)
So your vertex, what is it?
i dont know what is my vertex
Well then, look at your equation again y = 7(x - 7)² - 6 The vertex form of the parabola goes like y = a(x - h)² + k Where (h,k) is the vertex. Be extra careful with signs.
-7 and 6 are my vertex
I told you to be extra careful with signs...
what did i do wrong
-7 and -6
Well you see that in the form y = a ( x - h )² + k you have -h and not +h that should figure into your calculations
but is it max. or min.
We'll get to that once you know the vertex.
im kinda on a timed homework test can you give me the answer then explain plz
I prefer explaining first so that you can get the answer on your own. You'll feel better that way :)
where did we stop
y = a( x - h )² + k y = 7( x - 7 )² - 6 We were finding the values of h and k.
so you want me to solve the problem
yes, but hopefully, YOU want you to solve the problem too :)
how do you make 6 positve
at the end of the formula its +k i have a -6
Yeah, so you have +k = -6 So what's k?
i dont know thats why im telling you
That's already it, k = -6 now what's h?
You see, there'a difference, you have a -h in the vertex form and not just a normal h or +h
So, solve for h?
oh i just notice i made a mistake
the problem is f(x) = 7(x - 7)^2 - 6