anonymous
  • anonymous
Find area of the triangle? http://puu.sh/3dKTt.jpg
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
It's easy! You use 1/2 * SideAB * SideAC * sen79º
primeralph
  • primeralph
|dw:1371003691620:dw|
anonymous
  • anonymous
@zairhenrique so it's 601.25?

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anonymous
  • anonymous
|dw:1371003684934:dw|
anonymous
  • anonymous
Yes! 601.25
anonymous
  • anonymous
mm²
anonymous
  • anonymous
got it! easy. can you help with another? I have to find the side measurement: http://puu.sh/3dL0o.png still laws of cosine
anonymous
  • anonymous
laws of cosine? i think it's laws of sin.
anonymous
  • anonymous
i'm learning laws of cosine now. it's probably laws of sin, this is on a review for the entire unit
anonymous
  • anonymous
It's laws of sin. See it:
anonymous
  • anonymous
|dw:1371003900445:dw|
anonymous
  • anonymous
31/sin38º = b/sin74º b = 31*sin74º/sin38º
anonymous
  • anonymous
b = 48.4 48.4/74 = 50.35
anonymous
  • anonymous
no, no... b is the side.
anonymous
  • anonymous
well, 48.4/sin74
anonymous
  • anonymous
you want b.
anonymous
  • anonymous
just stop kk , its 48.4 rs
anonymous
  • anonymous
lol thank you.
anonymous
  • anonymous
http://puu.sh/3dLcu.png
anonymous
  • anonymous
You have to find the angle c, and after that, you will find the angle b. So, 13/sin40º = 19/sinc sinc = 19*sin40º/13
anonymous
  • anonymous
When you discover the angle c, just do 180 - 40º - c, and you will have the angle b :)
anonymous
  • anonymous
angle c is 69.96 right? i did your last equation 19 x sin40/13 then did arcsin with that answer and got 69.96
anonymous
  • anonymous
Yep, c is rounded to 70º.
anonymous
  • anonymous
got it :)
anonymous
  • anonymous
the answer is 70º. 180 - 40º - 70º = 70º
anonymous
  • anonymous
b = c
anonymous
  • anonymous
supposed to use laws of cosine for this one: http://puu.sh/3dLmF.png
anonymous
  • anonymous
yep!
anonymous
  • anonymous
Do you know how to do that?
anonymous
  • anonymous
the only law of cosine that was included in this lesson was cos C = a^2 + b^2 + c^2/2ab
anonymous
  • anonymous
Use that one: \[c²=a²+b²-2ab \cos \Theta \] |dw:1371004510363:dw|
anonymous
  • anonymous
In the picture that you posted, you have a, b, and theta, you just have to use the formula to find c :]
anonymous
  • anonymous
c = 169.26?
anonymous
  • anonymous
yep
anonymous
  • anonymous
rounded up to 169.3
anonymous
  • anonymous
how would i use laws of cosine to find an angle
anonymous
  • anonymous
Use my last draw and the equation will be: \[\cos \theta = \frac{ a² + b² - c² }{ 2ab }\]
anonymous
  • anonymous
and when you have the value of cos theta, just use arccos
anonymous
  • anonymous
so for this http://puu.sh/3dLNW.png i'd do 17^2 + 22^2 - 30^2, then divide by 2 x 17 x 22, then do arccos on that number
anonymous
  • anonymous
in this case, the 'c' of my formula is the side BC, of 17^2
anonymous
  • anonymous
so, the correct is 30^2+22^2-17^2 then divide by 2*30*22
anonymous
  • anonymous
okay gotcha
anonymous
  • anonymous
the 'c' in my formula is the side opposite to the angle that you want.
anonymous
  • anonymous
okay makes sense
anonymous
  • anonymous
are you on the highschool ?
anonymous
  • anonymous
yep! for tat answer i got 33.9
anonymous
  • anonymous
perfect
anonymous
  • anonymous
next one: http://puu.sh/3dLYk.png i'll do a^2 + b^2 - c^2, but it'll be more like this: 11^2 + 17^2 - 12^2, because b is across from the angle i'm solving for, right?
anonymous
  • anonymous
yes rs
anonymous
  • anonymous
dont forget to divide by 2*11*17
anonymous
  • anonymous
gotcha
anonymous
  • anonymous
my answer is 44.77 for that one
anonymous
  • anonymous
thats it
anonymous
  • anonymous
next one is: http://puu.sh/3dM9b.png j will be my c, so 7^2 + 6.58^2 - 10^2 / 2 x 7 x 6.58, then that answer for arccos
anonymous
  • anonymous
yep
anonymous
  • anonymous
i feel like this is much easier than laws of sine hahah
anonymous
  • anonymous
it's really much easier because there's a formula ready to give you the cos value rs
anonymous
  • anonymous
exactly! for that one i got 94.59 which rounds up to 95
anonymous
  • anonymous
thats right
anonymous
  • anonymous
for this one: http://puu.sh/3dMl7.png use the formula you gave me earlier: c^2 = a^2 + b^2 - 2ab cos theta
anonymous
  • anonymous
yep
anonymous
  • anonymous
9.5
anonymous
  • anonymous
9.5
anonymous
  • anonymous
;)
anonymous
  • anonymous
you're the most helpful person i've worked with on openstudy. thank you so much.
anonymous
  • anonymous
you're welcome :] i really like math so, it's fun for me being here rs

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