At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
|dw:1371007718302:dw| x-intercept, when y = 0
Okay, the correct answer is on that list...why don't you tell us what you think about each choice?
Well, I can see how it crosses the x axis at the origin. But I can't help but this there is more than one right answer
*can't help but think
Well, go through the list and tell us whether you think each one is possible or not. Explaining something to someone else is a great way to test and build your understanding.
you'll want to go through and see if the piecewise f(x) can = 0 within any of the 3 domains
I don't think the first one is possible, because as the graph shows, it doesn't cross at (2,0)
That's correct. Go on...
the second one was wrong because it does cross the x axis
Also, from the graph I see that it does cross at (16,0)
Are you sure about that?
I guess it doesn't, it just kinda...starts a different way once it gets there
it does cross at the origin and it doesn't cross at (0.5,0)
No, the last section starts at x = 4, not x = 16... it has y = 16 at that point, not x...
Oh,Okay I get that
As you can see, at x = 16, it's nowhere near the x-axis... Only 1 correct answer, agreed?
Right then, so it does cross at the origin. Which is my answer.
Yep, that's the only correct choice.
Thanks for going through it with me
You're welcome, of course!