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As one of the variables has matching coefficients in both equations, subtracting the two equations will give you an equation in a single variable, which you can easily solve. Then plug the value you found back into one of the original equations to find the value of the other variable. Then write the answer as (x,y)...
That answer which briefly winked in and out of existence has you do the same thing, except instead of subtracting, you multiply one equation all the way through by -1, then add. Exactly the same result, barring mistakes. For some (myself included) it might even be a slightly safer approach, because you don't have to worry about subtracting negative numbers.
What do you get for an answer?
I kind of forgot, it was on a quiz I was just taking :/
Lol well I saw your answer and was like...yeah subtracting would be easier @whpalmer4 so i deleted mine...2 different approaches at the same time can be confusing
Yep, it's hard to know in advance whether two slightly different (or not so slightly different) approaches will help or confuse any given student. I don't worry about it as much when the explanations are self-contained like these, but having multiple threads of posts probably confuses quite a few! Still, I would have loved as a student the opportunity to see so many problems solved in different ways...I learn something new here just about every day, even on problems I can solve in my sleep!
Right! lol granted I'm still a college student, but seeing how some of these problems get solved (calculus) is great because you see different approaches each time!
I saw someone do fraction subtraction as an algebra problem (which of course no one ever learns that way, because fractions are covered first) and my reaction was "where has that technique been all my life?!?" :-)
Actually that was like when I first saw someone solve a question regarding system of equations via matrices...and I said.....OMG....HOW SIMPLE! *I never learned matrices actually*