The test to detect the presence of a liver disorder is 98% accurate for a person who has the disease and 97% accurate for a person who does not have the disease. If 3.5% of the people in a given population actually have the disorder, what is the probability that a randomly chosen person tests positive?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
it is a lot easier to do this with numbers than with percents, although this is a probability question and we can use probabilities to solve it
lets say you have 1,000 people
since \(3.5\%\) have the disease, that means 35 people have it and therefore the rest, \(965\) do not have it
Not the answer you are looking for? Search for more explanations.
of the 35 who have the disease, 98% will test positive, so \(.98\times 35=34.3\) test positive
of the 965 who do not have it, 97% will test negative, and 3% will test positive
3% of 965 is \(.03\times 965=28.95\) test positive
the total number that test positive is therefore \(34.3+28.95=63.25\)