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RedDevil

  • one year ago

how do you evaluate C(9,7)

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  1. amistre64
    • one year ago
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    P(9,7)/7!

  2. amistre64
    • one year ago
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    9.8.7.6.5.4.3 ------------ 7.6.5.4.3.2.1 simplify to your hearts desire

  3. giolefpatceid
    • one year ago
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    C(n,k) can also be written: \[C(n,k) = \frac{n!}{k!(n-k)!}\]

  4. RedDevil
    • one year ago
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    What's The Answer ? A) 181,440 B)72 C)36 D)63

  5. amistre64
    • one year ago
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    please dont ask for an answer that you can work out for yourself ...

  6. amistre64
    • one year ago
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    \[C(n,k) = \frac{n!}{k!(n-k)!}\] \[C(n,k) = \frac{n!/(n-k)!}{k!}\] \[C(n,k) = \frac{P(n,k)}{k!}\]

  7. giolefpatceid
    • one year ago
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    \[C(9,7) = \frac{9!}{7!(9-7)!} = \frac{9!}{7!2!} = \frac{7!*8*9}{7!2!} = \frac{8*9}{2}\]

  8. RedDevil
    • one year ago
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    Thanks (: really Appreciate it..

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