anonymous
  • anonymous
How many grams of nitrogen dioxide may theoretically be produced when copper reacts completely with 21g of nitric acid? Cu + 4HNO3 ---> Cu(NO3)2 + 2H2O + 2NO2
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
It says the answer is 7.7 g. I don't know how to get it though. Please guide me through.
chmvijay
  • chmvijay
see 4 moles of HNO3 reacting with Cu produces 2 moles of NO2 right
anonymous
  • anonymous
ya

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chmvijay
  • chmvijay
can you tell molecular mass of HNO3 and NO2
anonymous
  • anonymous
63 and 46
anonymous
  • anonymous
So there is 1/3 mol of HN03
chmvijay
  • chmvijay
good :) now i convert those moles to gram using equation moles * molar mass =gram that is 4*63 gram of HNO3 will give rise to 2*46 g of NO2 then 21 gram of HNO3 gives = 21*2*46 /4*63 = 7.66
anonymous
  • anonymous
that is 4*63g/mol gives rise to 2*46g/mol right?
anonymous
  • anonymous
@chmvijay
chmvijay
  • chmvijay
Yaaa that also u can doo :) since they have asked in grams i have initially only converted to gram u may also convert moles to gram also :)
anonymous
  • anonymous
So basically, here we have 4 mol * 63g/mol gives rise to 2 mol * 46g/mol. The mols cancel out and u see that 252 g give rise to 92 g of NO2. Since there is only 21 g of HNO3 then 252/x = 21 implies x = 12. Dividing 92/12 = 7.66666. Correct? @chmvijay
chmvijay
  • chmvijay
yaaa :)

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