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 one year ago
Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5
 one year ago
Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5

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DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE \frac{dy}{dx}=2x+3=4\] \[\LARGE x=\frac{1}{2},y=\frac{11}{12}\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE (y\frac{11}{12})=4(x+\frac{1}{2})\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1other than that, your process is good

DLS
 one year ago
Best ResponseYou've already chosen the best response.012y48x+13=0 is what im getting :O

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1y = 5/4 y+5/4 = 4(x1/2) this is a line equation ... so if form does not matter this would suffice

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1otherwise, algrbrate it to your hearts content

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1.5^2 + 3(.5)  3 .25 + 1.5  3 1.75  3 = 1.25 = 5/4

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1since x = 1/2 and NOT 1/2 you have to reevaluate the y you found

DLS
 one year ago
Best ResponseYou've already chosen the best response.0arent we substituting x=1/2 in the equation of curve?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1yes, which is what i just did

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac14+\frac32\frac31\] \[\frac14+\frac64\frac{12}4\] \[\frac{712}4\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.0@amistre64 sorry,it was 3Y and not 3X that is how I got 11/12...

DLS
 one year ago
Best ResponseYou've already chosen the best response.0it is x squared so 1/2 and 1/2 both are same that is why i didnt change the y component

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1ohh then your derivative might need some looking at: x^2+3y3=0 2x +3y' = 0 y' = 2x/3 = 4 x = 12/2 = 6

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1(6)^2+3y3=0 33+3y=0, when y = 11

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1y+11 = 4(x+6) would be the tangent line
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