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DLS
 3 years ago
Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5
DLS
 3 years ago
Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5

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DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE \frac{dy}{dx}=2x+3=4\] \[\LARGE x=\frac{1}{2},y=\frac{11}{12}\]

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE (y\frac{11}{12})=4(x+\frac{1}{2})\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1other than that, your process is good

DLS
 3 years ago
Best ResponseYou've already chosen the best response.012y48x+13=0 is what im getting :O

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1y = 5/4 y+5/4 = 4(x1/2) this is a line equation ... so if form does not matter this would suffice

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1otherwise, algrbrate it to your hearts content

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1.5^2 + 3(.5)  3 .25 + 1.5  3 1.75  3 = 1.25 = 5/4

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1since x = 1/2 and NOT 1/2 you have to reevaluate the y you found

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0arent we substituting x=1/2 in the equation of curve?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1yes, which is what i just did

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac14+\frac32\frac31\] \[\frac14+\frac64\frac{12}4\] \[\frac{712}4\]

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 sorry,it was 3Y and not 3X that is how I got 11/12...

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0it is x squared so 1/2 and 1/2 both are same that is why i didnt change the y component

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1ohh then your derivative might need some looking at: x^2+3y3=0 2x +3y' = 0 y' = 2x/3 = 4 x = 12/2 = 6

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1(6)^2+3y3=0 33+3y=0, when y = 11

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1y+11 = 4(x+6) would be the tangent line
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