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Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5
 10 months ago
 10 months ago
Find the equation to the tangent to the curve x^2+3y3=0 which is parallel to the line y=4x5
 10 months ago
 10 months ago

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DLSBest ResponseYou've already chosen the best response.0
\[\LARGE \frac{dy}{dx}=2x+3=4\] \[\LARGE x=\frac{1}{2},y=\frac{11}{12}\]
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
\[\LARGE (y\frac{11}{12})=4(x+\frac{1}{2})\]
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
other than that, your process is good
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
12y48x+13=0 is what im getting :O
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
y = 5/4 y+5/4 = 4(x1/2) this is a line equation ... so if form does not matter this would suffice
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
otherwise, algrbrate it to your hearts content
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
.5^2 + 3(.5)  3 .25 + 1.5  3 1.75  3 = 1.25 = 5/4
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
since x = 1/2 and NOT 1/2 you have to reevaluate the y you found
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
arent we substituting x=1/2 in the equation of curve?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
yes, which is what i just did
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac14+\frac32\frac31\] \[\frac14+\frac64\frac{12}4\] \[\frac{712}4\]
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
@amistre64 sorry,it was 3Y and not 3X that is how I got 11/12...
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
it is x squared so 1/2 and 1/2 both are same that is why i didnt change the y component
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
ohh then your derivative might need some looking at: x^2+3y3=0 2x +3y' = 0 y' = 2x/3 = 4 x = 12/2 = 6
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
(6)^2+3y3=0 33+3y=0, when y = 11
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
y+11 = 4(x+6) would be the tangent line
 10 months ago
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