anonymous
  • anonymous
cos300-sin(90-B) --------------- cos(-B)+sin330 how would this be solved using identities
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
please anyone
ganeshie8
  • ganeshie8
use these : sin(90-B) = cosB cos(-B) = cosB sin(-B) = -sinB cos(x + 360) = cos(x) sin(x + 360) = sin(x)
anonymous
  • anonymous
i have but i get stuck here \[[(0.5)-cosB]/[cosb-1/2]\]

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ganeshie8
  • ganeshie8
wonderful! one more step you're done !!
dan815
  • dan815
ONE MOAR
dan815
  • dan815
ROW ROOW ROOWW YOUR BOAT
dan815
  • dan815
GENTLY DOWWNN THE STREAM
ganeshie8
  • ganeshie8
lol dan
dan815
  • dan815
moral support
ganeshie8
  • ganeshie8
\( [(0.5)-cosB]/[cosb-1/2] \) \(-1[cosB - 0.5]/[cosb-1/2] \)
anonymous
  • anonymous
is that factorisation
ganeshie8
  • ganeshie8
no, i just pulled -1 out
ganeshie8
  • ganeshie8
(a-b) = -(b-a)
anonymous
  • anonymous
ooh then you can cross cancel
ganeshie8
  • ganeshie8
exactly !
anonymous
  • anonymous
ooh thank you so much
ganeshie8
  • ganeshie8
np :)

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