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DLSBest ResponseYou've already chosen the best response.0
\[\Huge \sqrt{7+\sqrt{48}}=\sqrt{m}+\sqrt{n}\] solve for m^2+n^2
 10 months ago

marsssBest ResponseYou've already chosen the best response.2
\[\sqrt{7+\sqrt{48}}=\sqrt{7+2\sqrt{12}}\] m+n=7 and m*n=12 m=3 n=4 or m=4 n=3 3^2+4^2=9+16=25
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
how did you get all that? m+n=7 and m*n=12 m=3 n=4 or m=4 n=3 3^2+4^2=9+16=25
 10 months ago

marsssBest ResponseYou've already chosen the best response.2
\[(\sqrt{m}+\sqrt{n})^{2}=m+n+2\sqrt{mn}\] \[m+n+2\sqrt{mn}=7+2\sqrt{12 }\] do you understand?
 10 months ago

DLSBest ResponseYou've already chosen the best response.0
how can we compare btw,3 terms on one side 2 on other? :O
 10 months ago

marsssBest ResponseYou've already chosen the best response.2
m+n is just one term like 3+4. it's 7. did you get?
 10 months ago
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