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DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\Huge \sqrt{7+\sqrt{48}}=\sqrt{m}+\sqrt{n}\] solve for m^2+n^2
 one year ago

marsss Group TitleBest ResponseYou've already chosen the best response.2
\[\sqrt{7+\sqrt{48}}=\sqrt{7+2\sqrt{12}}\] m+n=7 and m*n=12 m=3 n=4 or m=4 n=3 3^2+4^2=9+16=25
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
how did you get all that? m+n=7 and m*n=12 m=3 n=4 or m=4 n=3 3^2+4^2=9+16=25
 one year ago

marsss Group TitleBest ResponseYou've already chosen the best response.2
\[(\sqrt{m}+\sqrt{n})^{2}=m+n+2\sqrt{mn}\] \[m+n+2\sqrt{mn}=7+2\sqrt{12 }\] do you understand?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
oh hmm okay thanks
 one year ago

marsss Group TitleBest ResponseYou've already chosen the best response.2
you're welcome :)
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
how can we compare btw,3 terms on one side 2 on other? :O
 one year ago

marsss Group TitleBest ResponseYou've already chosen the best response.2
m+n is just one term like 3+4. it's 7. did you get?
 one year ago
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