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anonymous
 3 years ago
A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) =  16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit.
i don't even understand what she is wanting me to do??????????
anonymous
 3 years ago
A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) =  16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit. i don't even understand what she is wanting me to do??????????

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goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0How ois the Physics question posted here @.Sam.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2math books have these types of questions as well

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2its asking you for the vertex of the parabola

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2if you can find the roots, you can determine the t value as the middle of the roots

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i Don't understand how to get to the vertex

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1371055357886:dw

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2can you find where the zeros for it are?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2then you are clearly not prepared to tackle this problem.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2can you factor the given equation?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i got to 16(t^2 + 36t)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.016t(t+36) = 16t (t+6) (t6)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.216t (t+36) is as far as you can go now the key here is to remember your zero times tables ....

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.216t (t+36) = 0 when 16t=0, or when t+36 = 0 what values do we get for "t"?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if 16t=0 then t is 0 and if t+36=0 then t=36

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2good, so lets say it takes from t= 0 to 36 seconds to go up and come back down to the ground. (h=0) the great thing about a parabola is that it takes the same amount of time to go up as it does to go down. the highest point is therefore, half of the time interval. what is half way between 0 and 36 ?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.2good, then it takes 18 seconds for it to reach its maximum position, and another 18 seconds to fall back down to the ground

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0h(t)=16t^2+576t \[\frac{ dh }{ dt }=32t+576\] when it is at maximum height dh/dt =0 32t+576=0,t=576/32=18 sec. when t=18 sec., h=16*18*18+576=18(16*18+32)=18*32(9+1)=576*8=4608 maximum height reached=4608 units.
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