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AValderrama16

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit. i don't even understand what she is wanting me to do??????????

  • 10 months ago
  • 10 months ago

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  1. goformit100
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    How ois the Physics question posted here @.Sam.

    • 10 months ago
  2. amistre64
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    math books have these types of questions as well

    • 10 months ago
  3. amistre64
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    its asking you for the vertex of the parabola

    • 10 months ago
  4. amistre64
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    if you can find the roots, you can determine the t value as the middle of the roots

    • 10 months ago
  5. AValderrama16
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    i Don't understand how to get to the vertex

    • 10 months ago
  6. amistre64
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    |dw:1371055357886:dw|

    • 10 months ago
  7. amistre64
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    can you find where the zeros for it are?

    • 10 months ago
  8. AValderrama16
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    No

    • 10 months ago
  9. amistre64
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    then you are clearly not prepared to tackle this problem.

    • 10 months ago
  10. amistre64
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    can you factor the given equation?

    • 10 months ago
  11. AValderrama16
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    yes i got to 16(t^2 + 36t)

    • 10 months ago
  12. amistre64
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    pull out a t as well

    • 10 months ago
  13. AValderrama16
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    16t(t+36) = 16t (t+6) (t-6)

    • 10 months ago
  14. amistre64
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    16t (t+36) is as far as you can go now the key here is to remember your zero times tables ....

    • 10 months ago
  15. AValderrama16
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    okay

    • 10 months ago
  16. amistre64
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    16t (-t+36) = 0 when 16t=0, or when -t+36 = 0 what values do we get for "t"?

    • 10 months ago
  17. AValderrama16
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    if 16t=0 then t is 0 and if -t+36=0 then -t=-36

    • 10 months ago
  18. amistre64
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    good, so lets say it takes from t= 0 to 36 seconds to go up and come back down to the ground. (h=0) the great thing about a parabola is that it takes the same amount of time to go up as it does to go down. the highest point is therefore, half of the time interval. what is half way between 0 and 36 ?

    • 10 months ago
  19. AValderrama16
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    18

    • 10 months ago
  20. amistre64
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    good, then it takes 18 seconds for it to reach its maximum position, and another 18 seconds to fall back down to the ground

    • 10 months ago
  21. AValderrama16
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    thank you :)

    • 10 months ago
  22. amistre64
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    good luck :)

    • 10 months ago
  23. surjithayer
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    h(t)=-16t^2+576t \[\frac{ dh }{ dt }=-32t+576\] when it is at maximum height dh/dt =0 -32t+576=0,t=576/32=18 sec. when t=18 sec., h=-16*18*18+576=18(-16*18+32)=18*32(-9+1)=576*-8=-4608 maximum height reached=4608 units.

    • 10 months ago
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