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A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) =  16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit.
i don't even understand what she is wanting me to do??????????
 10 months ago
 10 months ago
A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) =  16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit. i don't even understand what she is wanting me to do??????????
 10 months ago
 10 months ago

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goformit100Best ResponseYou've already chosen the best response.0
How ois the Physics question posted here @.Sam.
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
math books have these types of questions as well
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
its asking you for the vertex of the parabola
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
if you can find the roots, you can determine the t value as the middle of the roots
 10 months ago

AValderrama16Best ResponseYou've already chosen the best response.0
i Don't understand how to get to the vertex
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
dw:1371055357886:dw
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
can you find where the zeros for it are?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
then you are clearly not prepared to tackle this problem.
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
can you factor the given equation?
 10 months ago

AValderrama16Best ResponseYou've already chosen the best response.0
yes i got to 16(t^2 + 36t)
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
pull out a t as well
 10 months ago

AValderrama16Best ResponseYou've already chosen the best response.0
16t(t+36) = 16t (t+6) (t6)
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
16t (t+36) is as far as you can go now the key here is to remember your zero times tables ....
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
16t (t+36) = 0 when 16t=0, or when t+36 = 0 what values do we get for "t"?
 10 months ago

AValderrama16Best ResponseYou've already chosen the best response.0
if 16t=0 then t is 0 and if t+36=0 then t=36
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
good, so lets say it takes from t= 0 to 36 seconds to go up and come back down to the ground. (h=0) the great thing about a parabola is that it takes the same amount of time to go up as it does to go down. the highest point is therefore, half of the time interval. what is half way between 0 and 36 ?
 10 months ago

amistre64Best ResponseYou've already chosen the best response.2
good, then it takes 18 seconds for it to reach its maximum position, and another 18 seconds to fall back down to the ground
 10 months ago

surjithayerBest ResponseYou've already chosen the best response.0
h(t)=16t^2+576t \[\frac{ dh }{ dt }=32t+576\] when it is at maximum height dh/dt =0 32t+576=0,t=576/32=18 sec. when t=18 sec., h=16*18*18+576=18(16*18+32)=18*32(9+1)=576*8=4608 maximum height reached=4608 units.
 10 months ago
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