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AValderrama16 Group Title

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t2 + 576t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit. i don't even understand what she is wanting me to do??????????

  • one year ago
  • one year ago

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  1. goformit100 Group Title
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    How ois the Physics question posted here @.Sam.

    • one year ago
  2. amistre64 Group Title
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    math books have these types of questions as well

    • one year ago
  3. amistre64 Group Title
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    its asking you for the vertex of the parabola

    • one year ago
  4. amistre64 Group Title
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    if you can find the roots, you can determine the t value as the middle of the roots

    • one year ago
  5. AValderrama16 Group Title
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    i Don't understand how to get to the vertex

    • one year ago
  6. amistre64 Group Title
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    |dw:1371055357886:dw|

    • one year ago
  7. amistre64 Group Title
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    can you find where the zeros for it are?

    • one year ago
  8. AValderrama16 Group Title
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    No

    • one year ago
  9. amistre64 Group Title
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    then you are clearly not prepared to tackle this problem.

    • one year ago
  10. amistre64 Group Title
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    can you factor the given equation?

    • one year ago
  11. AValderrama16 Group Title
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    yes i got to 16(t^2 + 36t)

    • one year ago
  12. amistre64 Group Title
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    pull out a t as well

    • one year ago
  13. AValderrama16 Group Title
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    16t(t+36) = 16t (t+6) (t-6)

    • one year ago
  14. amistre64 Group Title
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    16t (t+36) is as far as you can go now the key here is to remember your zero times tables ....

    • one year ago
  15. AValderrama16 Group Title
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    okay

    • one year ago
  16. amistre64 Group Title
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    16t (-t+36) = 0 when 16t=0, or when -t+36 = 0 what values do we get for "t"?

    • one year ago
  17. AValderrama16 Group Title
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    if 16t=0 then t is 0 and if -t+36=0 then -t=-36

    • one year ago
  18. amistre64 Group Title
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    good, so lets say it takes from t= 0 to 36 seconds to go up and come back down to the ground. (h=0) the great thing about a parabola is that it takes the same amount of time to go up as it does to go down. the highest point is therefore, half of the time interval. what is half way between 0 and 36 ?

    • one year ago
  19. AValderrama16 Group Title
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    18

    • one year ago
  20. amistre64 Group Title
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    good, then it takes 18 seconds for it to reach its maximum position, and another 18 seconds to fall back down to the ground

    • one year ago
  21. AValderrama16 Group Title
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    thank you :)

    • one year ago
  22. amistre64 Group Title
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    good luck :)

    • one year ago
  23. surjithayer Group Title
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    h(t)=-16t^2+576t \[\frac{ dh }{ dt }=-32t+576\] when it is at maximum height dh/dt =0 -32t+576=0,t=576/32=18 sec. when t=18 sec., h=-16*18*18+576=18(-16*18+32)=18*32(-9+1)=576*-8=-4608 maximum height reached=4608 units.

    • one year ago
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