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114325

  • 2 years ago

write (27a^-9)^-2/3 in simplest form please help me ive been stuck on this for like 20 minutes now

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  1. brandeejo
    • 2 years ago
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    a^18/2187

  2. giolefpatceid
    • 2 years ago
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    \[(27a^{-9})^{-\frac{2}{3}} = 27^{-\frac{2}{3}}(a^{-9})^{-\frac{2}{3}} = (3^3)^{-\frac{2}{3}}(a^{-9})^{-\frac{2}{3}}\] \[=3^{-3\frac{2}{3}}a^{-9\frac{-2}{3}} = 3^{-2}a^{6} = \frac{1}{3^2}a^6= \frac{1}{9}a^6\]

  3. giolefpatceid
    • 2 years ago
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    @amistre64 Could you please validate my solution? Thank you in advance!

  4. giolefpatceid
    • 2 years ago
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    I think my solution is valid if a is positive.

  5. amistre64
    • 2 years ago
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    even if a is negative its fine

  6. giolefpatceid
    • 2 years ago
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    Thank you very much!

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