• anonymous
From top of a tower, a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in time t2. A third stone is released from rest and it reaches the ground in time t3. Then: a) t3=1/2(t1+t2) b)t3=sqrt(t1t2) c)1/t3=1/t2-1/t1 d)t3^2=t1^2-t2^2
Physics
• Stacey Warren - Expert brainly.com
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SOLVED
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