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find the point on the plane that the xyz of the line fits

For paramatric equation of the line I got
X = 1+2t
Y = -2 –t
Z = -3t

yes

|dw:1371056632838:dw|

im thinking we need to go another route, find the angle between the normal and the line

i can never remember the formula, so i tend to go a longer route.

|dw:1371057451397:dw|

19*sqrt(2) = 19sqrt(2)
10sqrt(7)*sqrt(2) = 10sqrt(14) = t to define the point is what im thinking

by all means :)

Once again thank you so much for your help, you're many people's hero :)

youre welcome :)