anonymous
  • anonymous
Solve for a. What is the root?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1371056665064:dw|
anonymous
  • anonymous
The square root of 5a plus 2 minus the square root of 7a minus 8 equals 0.
mathstudent55
  • mathstudent55
Add the second root to both sides so you have one root on each side of the equal sign. Then square both sides to get rid of the roots. Try it and show what you get.

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anonymous
  • anonymous
The 2nd \[\sqrt{7a-8}\]
anonymous
  • anonymous
is that right?
anonymous
  • anonymous
@mathstudent55 5a + 2^2 - 7a -8^2
mathstudent55
  • mathstudent55
No. Read what I wrote above carefully. You picked the correct root. Now add it to both sides. You end up with a root on each side. Then square both sides to get rifd of both square root symbols.
mathstudent55
  • mathstudent55
|dw:1371057117719:dw|
anonymous
  • anonymous
Ohhh. Sorry about that. Now I see what you meant.
mathstudent55
  • mathstudent55
|dw:1371057154807:dw|
mathstudent55
  • mathstudent55
Ok. I showed you what I meant. I added the second root to both sides to get it on the right side. Then I squared both sides to get rid of the square roots.
anonymous
  • anonymous
So what is the root?
mathstudent55
  • mathstudent55
You have two small exponents that should not be there. Look at what I have above.
mathstudent55
  • mathstudent55
|dw:1371057417539:dw|
mathstudent55
  • mathstudent55
|dw:1371057581819:dw|
anonymous
  • anonymous
Ohh I get it now. Sorry for my misunderstanding.
mathstudent55
  • mathstudent55
Now you need to plug in 5 in for a in the original equation to make sure it works.
mathstudent55
  • mathstudent55
It's no problem at all. It's all part of the process of studying.
mathstudent55
  • mathstudent55
The reason you need to plug in the solution in the original equation is that the squaring process sometimes introduces extraneous solutions that are false.
anonymous
  • anonymous
I tried it and it works! Thanks a bunch!!
mathstudent55
  • mathstudent55
wlcm

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