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Johnmathstudent
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If I flip four coins what is the probability that at least two of the coins are heads?
 one year ago
 one year ago
Johnmathstudent Group Title
If I flip four coins what is the probability that at least two of the coins are heads?
 one year ago
 one year ago

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Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
Please help
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
its the opposite of P(at most 1 is heads)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
1  P(0)  P(1)
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
do you have choices
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
there are 16 outcomes tttt ttth ttht thtt httt ... 1 4 6 4 1 = 16 0 heads is 1 out of 16 1 head is 4 out of 16
 one year ago

Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
What about at least 2 heads
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
at least 2 heads means that you have 2, 3, or 4 heads P(0) + P(1) + P(2) + P(3) + P(4) = 1 P(2) + P(3) + P(4) = 1  P(0)  P(1)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
since P(0) = 1/16 and P(1) = 4/16 the solution is determined
 one year ago

Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
So what would the answer be written as?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im not going to do the subtraction for you ....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
you can tell me what you get ... and i can verify if you did it correctly
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
bro your even confusing me.... amistre64
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im not a mind reader, so youll have to be more detailed in what is confusing :)
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
nevermind .. the probability would be 50% John
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the probability is not 50%; for starters, a probability is a number between 0 and 1 ... not a percentage.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
and for another, 1  P(0)  P(1) does not equal .5000 or 1/2
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
he asked for a probability. if you flip 4 coins and the odds of 2 of the comming out heads is 2/4 and tht equals 50% and wtf is p
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
its not rocket science he just wants a simple answer.. idk whats wrong with tht
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[\binom{4}{0}.5^0.5^4+\binom{4}{1}.5^1.5^3+\binom{4}{2}.5^2.5^2+\binom{4}{3}.5^3.5^1+\binom{4}{4}.5^n.4^0=1\] \[(1).5^0.5^4+(4).5^1.5^3+(6).5^2.5^2+(4).5^3.5^1+(1).5^4.5^0=1\]
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
P(E) is notation for "probability of an event"
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
the last 3 terms are 4 choose 2, 4 choose 3, and 4 choose 4 which is what we want if we are to determine "at least 2" out of 4
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
subtracting the first 2 terms from each side gives us the solution
 one year ago

MAYSTEPH Group TitleBest ResponseYou've already chosen the best response.0
your making this way more complex than it already isnt lol if you know the damn answer then tell him and quit arguing with a degenerate!
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i suggest you tone down your language. and, we are not providing a free answering service, we are offering a way to learn the material.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
my first attempt was to simplify it .... since that did not work i resorted to the longer, more detailed version of it all.
 one year ago

Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
So the answer is .6875?
 one year ago

Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
Or 11/16
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
11/16 is correct either way is fine, but the format is up to whoever is doing the grading.
 one year ago

Johnmathstudent Group TitleBest ResponseYou've already chosen the best response.0
Thanks I just forgot how to do this from the beginning of the year
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
you did fine :) good luck
 one year ago
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