A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 2 years ago
why in common emitter output wave is 180 out of phase?
anonymous
 2 years ago
why in common emitter output wave is 180 out of phase?

This Question is Closed

KenLJW
 2 years ago
Best ResponseYou've already chosen the best response.0The common emitter mode, taking output from collector, actually has a positive current gain which causes the drop across the load to increase thereby decreasing the voltage at the collector. The above uses the standard convention that input/output currents and considered positive into their respective node. If you take the output across an emitter resistor in this mode the output is in phase with the input, usually with a gain close to one.

arnavguddu
 2 years ago
Best ResponseYou've already chosen the best response.0for CE we can write the KVL at output as V0 = VCE = Vcc  IcRc eliminated the emitter Resistance No Ic = B Ib where B = beta gain So differentiate the output KVL we get dV0 = dIc Rc = dIb B Rc as B and Rc are assumed constant for our CE circuit The  sign indicates that phase of output voltage is 180 deg out of phase with Input current. Input current being function of input voltage, u get Input voltage and Output voltage are 180 out of phase. This is the mathametical explanation....

Koikkara
 2 years ago
Best ResponseYou've already chosen the best response.0For more Information.... http://www.ask.com/faqcentral/PHASE_180.html Thank you
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.