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Ali_Nawaz

  • 2 years ago

why in common emitter output wave is 180 out of phase?

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  1. KenLJW
    • 2 years ago
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    The common emitter mode, taking output from collector, actually has a positive current gain which causes the drop across the load to increase thereby decreasing the voltage at the collector. The above uses the standard convention that input/output currents and considered positive into their respective node. If you take the output across an emitter resistor in this mode the output is in phase with the input, usually with a gain close to one.

  2. arnavguddu
    • 2 years ago
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    for CE we can write the KVL at output as V0 = VCE = Vcc - IcRc eliminated the emitter Resistance No Ic = B Ib where B = beta gain So differentiate the output KVL we get dV0 = -dIc Rc = -dIb B Rc as B and Rc are assumed constant for our CE circuit The - sign indicates that phase of output voltage is 180 deg out of phase with Input current. Input current being function of input voltage, u get Input voltage and Output voltage are 180 out of phase. This is the mathametical explanation....

  3. Koikkara
    • 2 years ago
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    For more Information.... http://www.ask.com/faqcentral/PHASE_180.html Thank you

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