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anonymous
 3 years ago
I cant seem to find the answer to this can anyone help me?
anonymous
 3 years ago
I cant seem to find the answer to this can anyone help me?

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jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0well, do you know how to do system of equations?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeahbut i cant seem to find the answer i get (4,6) . ? @jdoe0001

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by 1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times 1 \\ \hline\\ ? & ? & ? \end{matrix} $$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its the last one... use cramers rules

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1id suggest just testing out the options to see what fits ....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No problem, i do suggest using youtube to learn how to do Cramer's Rule

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0omg i had totaly forgor that system @amistre64

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0youtubes super helpful too i also forgot about that too ._. @drotzmann

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by 7/6}\\ \begin{matrix} 5x &+7y & =32 \\ \frac{28}{3}x & 7y & =\frac{161}{3} & \times \color{blue}{\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix} $$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0three 2x2's to be correct ;)

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants
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