Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

lunitaboo

I cant seem to find the answer to this can anyone help me?

  • 10 months ago
  • 10 months ago

  • This Question is Closed
  1. lunitaboo
    Best Response
    You've already chosen the best response.
    Medals 0

    • 10 months ago
    1 Attachment
  2. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    well, do you know how to do system of equations?

    • 10 months ago
  3. lunitaboo
    Best Response
    You've already chosen the best response.
    Medals 0

    yeahbut i cant seem to find the answer i get (4,6) -.- ? @jdoe0001

    • 10 months ago
  4. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    $$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by -1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times -1 \\ \hline\\ ? & ? & ? \end{matrix} $$

    • 10 months ago
  5. Luigi0210
    Best Response
    You've already chosen the best response.
    Medals 2

    matrix seemed easier

    • 10 months ago
  6. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    its the last one... use cramers rules

    • 10 months ago
  7. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    (5,1)

    • 10 months ago
  8. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    matrix? w000t?

    • 10 months ago
  9. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    hmmm

    • 10 months ago
  10. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    hold on

    • 10 months ago
  11. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    -1 will not the trick

    • 10 months ago
  12. lunitaboo
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks @drotzmann

    • 10 months ago
  13. amistre64
    Best Response
    You've already chosen the best response.
    Medals 1

    id suggest just testing out the options to see what fits ....

    • 10 months ago
  14. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    No problem, i do suggest using youtube to learn how to do Cramer's Rule

    • 10 months ago
  15. lunitaboo
    Best Response
    You've already chosen the best response.
    Medals 0

    omg i had totaly forgor that system @amistre64

    • 10 months ago
  16. lunitaboo
    Best Response
    You've already chosen the best response.
    Medals 0

    youtubes super helpful too i also forgot about that too ._. @drotzmann

    • 10 months ago
  17. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    haha:)

    • 10 months ago
  18. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"

    • 10 months ago
  19. amistre64
    Best Response
    You've already chosen the best response.
    Medals 1

    in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)

    • 10 months ago
  20. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    $$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by -7/6}\\ \begin{matrix} 5x &+7y & =32 \\ -\frac{28}{3}x & -7y & =-\frac{161}{3} & \times \color{blue}{-\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix} $$

    • 10 months ago
  21. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    @jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier

    • 10 months ago
  22. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)

    • 10 months ago
  23. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    three 2x2's to be correct ;)

    • 10 months ago
  24. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants

    • 10 months ago
  25. jdoe0001
    Best Response
    You've already chosen the best response.
    Medals 0

    determinants rather

    • 10 months ago
  26. drotzmann
    Best Response
    You've already chosen the best response.
    Medals 0

    yup:) exactly

    • 10 months ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.