anonymous
  • anonymous
I cant seem to find the answer to this can anyone help me?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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jdoe0001
  • jdoe0001
well, do you know how to do system of equations?
anonymous
  • anonymous
yeahbut i cant seem to find the answer i get (4,6) -.- ? @jdoe0001

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jdoe0001
  • jdoe0001
$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by -1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times -1 \\ \hline\\ ? & ? & ? \end{matrix} $$
Luigi0210
  • Luigi0210
matrix seemed easier
anonymous
  • anonymous
its the last one... use cramers rules
anonymous
  • anonymous
(5,1)
jdoe0001
  • jdoe0001
matrix? w000t?
jdoe0001
  • jdoe0001
hmmm
jdoe0001
  • jdoe0001
hold on
jdoe0001
  • jdoe0001
-1 will not the trick
anonymous
  • anonymous
thanks @drotzmann
amistre64
  • amistre64
id suggest just testing out the options to see what fits ....
anonymous
  • anonymous
No problem, i do suggest using youtube to learn how to do Cramer's Rule
anonymous
  • anonymous
omg i had totaly forgor that system @amistre64
anonymous
  • anonymous
youtubes super helpful too i also forgot about that too ._. @drotzmann
anonymous
  • anonymous
haha:)
jdoe0001
  • jdoe0001
well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"
amistre64
  • amistre64
in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)
jdoe0001
  • jdoe0001
$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by -7/6}\\ \begin{matrix} 5x &+7y & =32 \\ -\frac{28}{3}x & -7y & =-\frac{161}{3} & \times \color{blue}{-\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix} $$
anonymous
  • anonymous
@jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier
jdoe0001
  • jdoe0001
hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)
anonymous
  • anonymous
three 2x2's to be correct ;)
jdoe0001
  • jdoe0001
hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants
jdoe0001
  • jdoe0001
determinants rather
anonymous
  • anonymous
yup:) exactly

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