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jdoe0001Best ResponseYou've already chosen the best response.0
well, do you know how to do system of equations?
 10 months ago

lunitabooBest ResponseYou've already chosen the best response.0
yeahbut i cant seem to find the answer i get (4,6) . ? @jdoe0001
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by 1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times 1 \\ \hline\\ ? & ? & ? \end{matrix} $$
 10 months ago

Luigi0210Best ResponseYou've already chosen the best response.2
matrix seemed easier
 10 months ago

drotzmannBest ResponseYou've already chosen the best response.0
its the last one... use cramers rules
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
1 will not the trick
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
id suggest just testing out the options to see what fits ....
 10 months ago

drotzmannBest ResponseYou've already chosen the best response.0
No problem, i do suggest using youtube to learn how to do Cramer's Rule
 10 months ago

lunitabooBest ResponseYou've already chosen the best response.0
omg i had totaly forgor that system @amistre64
 10 months ago

lunitabooBest ResponseYou've already chosen the best response.0
youtubes super helpful too i also forgot about that too ._. @drotzmann
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"
 10 months ago

amistre64Best ResponseYou've already chosen the best response.1
in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by 7/6}\\ \begin{matrix} 5x &+7y & =32 \\ \frac{28}{3}x & 7y & =\frac{161}{3} & \times \color{blue}{\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix} $$
 10 months ago

drotzmannBest ResponseYou've already chosen the best response.0
@jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)
 10 months ago

drotzmannBest ResponseYou've already chosen the best response.0
three 2x2's to be correct ;)
 10 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants
 10 months ago
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