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jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well, do you know how to do system of equations?

lunitaboo
 one year ago
Best ResponseYou've already chosen the best response.0yeahbut i cant seem to find the answer i get (4,6) . ? @jdoe0001

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by 1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times 1 \\ \hline\\ ? & ? & ? \end{matrix} $$

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2matrix seemed easier

drotzmann
 one year ago
Best ResponseYou've already chosen the best response.0its the last one... use cramers rules

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.01 will not the trick

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1id suggest just testing out the options to see what fits ....

drotzmann
 one year ago
Best ResponseYou've already chosen the best response.0No problem, i do suggest using youtube to learn how to do Cramer's Rule

lunitaboo
 one year ago
Best ResponseYou've already chosen the best response.0omg i had totaly forgor that system @amistre64

lunitaboo
 one year ago
Best ResponseYou've already chosen the best response.0youtubes super helpful too i also forgot about that too ._. @drotzmann

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0$$ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by 7/6}\\ \begin{matrix} 5x &+7y & =32 \\ \frac{28}{3}x & 7y & =\frac{161}{3} & \times \color{blue}{\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix} $$

drotzmann
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)

drotzmann
 one year ago
Best ResponseYou've already chosen the best response.0three 2x2's to be correct ;)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants
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