lunitaboo Group Title I cant seem to find the answer to this can anyone help me? one year ago one year ago

1. lunitaboo Group Title

2. jdoe0001 Group Title

well, do you know how to do system of equations?

3. lunitaboo Group Title

yeahbut i cant seem to find the answer i get (4,6) -.- ? @jdoe0001

4. jdoe0001 Group Title

$$\begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix} \text{multiply the 2nd by -1}\\ \begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 & \times -1 \\ \hline\\ ? & ? & ? \end{matrix}$$

5. Luigi0210 Group Title

matrix seemed easier

6. drotzmann Group Title

its the last one... use cramers rules

7. drotzmann Group Title

(5,1)

8. jdoe0001 Group Title

matrix? w000t?

9. jdoe0001 Group Title

hmmm

10. jdoe0001 Group Title

hold on

11. jdoe0001 Group Title

-1 will not the trick

12. lunitaboo Group Title

thanks @drotzmann

13. amistre64 Group Title

id suggest just testing out the options to see what fits ....

14. drotzmann Group Title

No problem, i do suggest using youtube to learn how to do Cramer's Rule

15. lunitaboo Group Title

omg i had totaly forgor that system @amistre64

16. lunitaboo Group Title

17. drotzmann Group Title

haha:)

18. jdoe0001 Group Title

well, to cancel out the "y" I'd just do 6 * n = 7 n = 7/6 thus 6 * 7/6 = 7 that gives you a 7y at the bottom, thus cancelling out "y"

19. amistre64 Group Title

in kindergarten, i was confronted by a hole shaped like a triangle, and 4 blocks oddly shaped blocks. instead of measuring stuff and trying to work out some complicated things ... i just picked up each block till i found the one that fit :)

20. jdoe0001 Group Title

$$\begin{matrix} 5x &+7y & =32 \\ 8x & +6y & =46 \\ \hline \end{matrix}\\ \text{multiply the 2nd by -7/6}\\ \begin{matrix} 5x &+7y & =32 \\ -\frac{28}{3}x & -7y & =-\frac{161}{3} & \times \color{blue}{-\frac{7}{6}} \\ \hline\\ ? & 0 & ? \end{matrix}$$

21. drotzmann Group Title

@jdoe0001 ....one of us is on crack... i have no idea what you are doing. Cramer's Rule is so much more easier

22. jdoe0001 Group Title

hehhe, yes, because is a 2x2, well, yeah, I gather you'd use that :)

23. drotzmann Group Title

three 2x2's to be correct ;)

24. jdoe0001 Group Title

hehe, yes, not sure ... if it'd be .... I guess it depends I mean, off you have to get the discriminant, then 2 more discriminants

25. jdoe0001 Group Title

determinants rather

26. drotzmann Group Title

yup:) exactly