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@jim_thompson5910 @amistre64 I've been stuck on this problem for so long and I really need the answer to this and a few others!
I don't know @jim_thompson5910
sin? theta? i'm really not sure
0? I don't know. There aren't numbers in the equation..
I don't know how to do that.. Sorry, I've been doing math homework all day and my brain is kind of fried, lol.
I'm sorry, I don't know how to write the problem and do it in order to solve it. I suck at math.
my computer isn't loading the page
all real numbers except multiples of pi, because that's when the denominator would equal 0 (csc = 1/sin)
thank you :D @mangorox
No problem @icedancerfigureskater
Can I have help with just a few more? @mangorox
I'll try to help
Ok. What is the radian measure of an angle whose tangent is -0.25? My answers are: -1.33, 0.24, 2.9, and 4.95
Ok let me see...
i'm sorry I don't know the answer to this question :(
It's okay, do you think you can help me with a question using unit circles and inverse functions? @mangorox
I can try, it depends on the question.
Okay. Use the unit circle to find the inverse function value in degrees. cos^-1 (sqrt3/2)
Does this help?: the unit circle can help you find the correct quadrants, but you have to memorize the actual degrees. You should know the sin, cos and tan of 0º, 30º, 45º, 60º, and 90º there is a pattern for sin: 0 1/2 sqrt(2)/2 sqrt(3)/2 1 if we use sqrt(0) is 0 and sqrt(1) is 1 and the sqrt(4) is 2, the pattern is sqrt(0)/2 sqrt(1)/2 sqrt(2)/2 sqrt(3)/2 sqrt(4)/2 cosine goes in the other direction tangent is sin/cos
Kind of, but I don't know how to get my answer
ok what is the sin(60º) ? the answer is : memorize it. See above. it is a number between -1 and 1. In this case 0.866025403... and on and on rather than type all the numbers people give the equivalent sqrt(3)/2 type sin(60 degrees)= in the google search window. It will give you that number type sqrt(3)/2= in the google search window. It will give the same number
This might help also: http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry
the answer they want (I am assuming) is sin−1(3√2)=60º and 120º
the answer is 60 degrees, thank you.
Do you know how to solve this one? @mangorox Simplify the trigonometric expression. sin^2 θ /1-cosθ
Sorry, I don't know how to solve that one
Ok, that's fine.
17. Verify the pythagorean identity. 1+cot^2 θ =csc^2 θ @DLe @mangorox @jim_thompson5910 @amistre64 @dan815
cot^2 θ = (cos^2 θ) / (sin^2 θ) so, 1 + (cos^2 θ) / (sin^2 θ) = [sin^2 θ + cos^2 θ] / (sin^2 θ) = 1 / (sin^2 θ) = csc^2 θ qed
Thank you! @mangorox I only have one more that I need help with if you can. 18. Verify the identity. tan θ + cot θ = 1/ sinθ cosθ
tan A + cot A =?= 1/(sinA cosA) tan A = sinA / cosA cot A = cosA / sinA So, sinA/cosA + cosA/sinA = 1/(sinAcosA) multiply both sides by sinAcosA sinAcosA (sinA/cosA) + sinAcosA(cosA/sinA) = 1 sin^A + cos^2A = 1
Thank you so very much!!! @mangorox
No problem! :) @icedancerfigureskater