anonymous
  • anonymous
Anyone? Let f(x) = x + 2 and g(x) = x2 – 6x + 3. Find g(f(x)). x2 – 6x + 5 x2 – 5x + 5 x2 – 2x – 5 x2 + 10x + 19
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jdoe0001
  • jdoe0001
think of it this way g( f(x) ) ^ g is HOSTING f(x), who is inside
jdoe0001
  • jdoe0001
so any "x" in the HOST function, will be replace by the GUEST function
anonymous
  • anonymous
wait what? I'm a little bit confused.

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jdoe0001
  • jdoe0001
$$ f(x) = \color{red}{x+2}\\ g(x) = x^2-6x+3\\ g ( f(x) ) = (\color{red}{x+2})^2-6(\color{red}{x+2})+3 $$
jdoe0001
  • jdoe0001
so, expand that, cancel like-terms, and you'd get g(f(x))
anonymous
  • anonymous
Well, f(x) = x + 2, so we plug that in for the x values of g(x), so: g(f(x)) = (x + 2)^2 - 6(x + 2) + 3 = x^2 + 4x + 4 - 6x - 12 + 3 = x^2 - 2x - 5
anonymous
  • anonymous
Okay thank you. I get it now.
jdoe0001
  • jdoe0001
yw

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